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cestrela7 [59]
3 years ago
10

Est ce qu’un cricket c’est un consommateur

Physics
1 answer:
Sholpan [36]3 years ago
7 0

Answer:

Oui

Explanation:

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Write any two different between work and power?​
attashe74 [19]

Answer:

1. Work Is a type of Physical Activity  

2. Power is Basically Having control of Society

Explanation:

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if the time is taken to bring a ball to rest from a certain velocity 'v'. is reduced to half, what will be the change in the val
777dan777 [17]

The answer is C) rate of change of momentum. The answer is not initial or final momentum as the start and end points are not changing. On the other hand, the time it takes for the ball to change velocity is. This change relates to the change of momentum. Hope this helped :))

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16) A man ran a 5 mile race. The race looped around a city park and back
finlep [7]

Answer:

The man's total displacement is equal to 0.

Explanation:

Given that,

A man ran a 5 mile race. The race looped around a city park and back  to the starting line.

We need to find the total displacement of the man.

We know that,

Displacement = shortest path covered

Also,

Displacement = final position - initial position

As it reaches back to its starting line, it means, the displacement is equal to 0.

Hence, the man's total displacement is equal to 0.

3 0
3 years ago
What are the effect of propagation of light​
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                               ∵∴∵∴∵∴∵∴∵∴∵∴∵∴∵∴∵∴∵∴∵∴∵∴

Due to Rectilinear propagation of light  

  • A shadow is formed
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7 0
3 years ago
When the displacement in SHM is equal to 1/4 of the amplitude xm, what fraction of the total energy is (a) kinetic energy and (b
Anna71 [15]

Answer:

\frac{KE}{TE} = \frac{15}{16}

b)

\frac{U}{TE} = \frac{1}{16}

Explanation:

Let the amplitude of SHM is given as A

so the total energy of SHM is given as

E = \frac{1}{2}kA^2

now we know that

a)

kinetic energy is given as

KE = \frac{1}{2}k(A^2 - x^2)

here

x = \frac{A}{4}

so now we have

KE = \frac{1}{2}k(A^2 - \frac{A^2}{16})

KE = \frac{15}{32}kA^2

now its fraction with respect to total energy is given as

\frac{KE}{TE} = \frac{15}{16}

b)

Potential energy is given as

U = \frac{1}{2}kx^2

so we have

U = \frac{1}{32}kA^2

so fraction of energy is given as

\frac{U}{TE} = \frac{1}{16}

7 0
3 years ago
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