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cestrela7 [59]
3 years ago
10

Est ce qu’un cricket c’est un consommateur

Physics
1 answer:
Sholpan [36]3 years ago
7 0

Answer:

Oui

Explanation:

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What is the free-throw line used for?
Genrish500 [490]

Answer:

it be the second one lad

Explanation:

i have done the playing pf the basketball

5 0
3 years ago
the volume of a water tank is 5m×4m×2m. If the tank is half filled with water. calculate the pressure exerted at the bottom of t
Natali5045456 [20]

Answer:

10⁴ Pa

Explanation:

  • Volume = 5m * 4m * 2m

When the tank is half filled ,

  • Volume = 5m * 4m * 1m = 20m³

Also we know that ,

  • Density of water = 10³ kg/ m³

\longrightarrow Density = Mass/Volume

\longrightarrow 10³ kg/m³ = m/20m³

\longrightarrow m = 2 * 10⁴ kg

So that ,

\longrightarrow Weight = mg

\longrightarrow F = 2*10⁴ × 10 N

\longrightarrow F = 2 * 10⁵ N

And ,

\longrightarrow Pressure = Force/Area

\longrightarrow P = 2 *10⁵/ 5 * 4 Pa

\longrightarrow P = 10⁴ Pa

5 0
2 years ago
How does the way that matter cycles through an ecosystem differ from the way that energy flows?
guapka [62]

Unlike the one-way flow of energy, matter is recycled within and between ecosystems. Every living organism needs nutrients to build tissues and carry out essential life functions.

7 0
3 years ago
Use the table to answer the question.
QveST [7]

Answer:

Mechanical Waves

Explanation:

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6 0
2 years ago
A bubble, located 0.200 m beneath the surface in a glass of beer, rises to the top. The air pressure at the top is 1.01x10⁵ Pa.
Cerrena [4.2K]

Answer:

\frac{1.019}{1}

Explanation:

To solve this equation we will have to consider that the bubble is filled with an Ideal Gas and as such we can use the Ideal Gas Law

PV = nRT

Where

P = Pressure

V = Volume

n = Moles

R = Ideal Gas Constant

T  = Temperature

Now since we know that the value for the temperature and moles is constant we can simply use Boyles Law for the two states

P_{1} V_{1} =P_{2} V_{2}

Let us look at the two states

State 1 (at top)

Pressure = 1.01*10^5

Volume = V_{1}

State 2 (at bottom)

Pressure = 1.01*10^5 + dgh

Where

d = Density of liquid (1000 kg/m³)

d = Acceleration due to gravity (9.8 m/s²)

d = Height of liquid (0.200 m)

Pressure = 102,962

Volume = V_{2}

Inputting these values into the Boyles Law

P_{1} V_{1} =P_{2} V_{2}\\ (101000)V_{1} = (102962)V_{2}\\ \frac{V_{1}}{V_{2}} = \frac{102962}{101000} \\  \frac{V_{1}}{V_{2}} = \frac{1.019}{1}

6 0
2 years ago
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