Answer:
the magnitude of the angular magnification of the telescope. is 4
Explanation:
Calculate the magnitude of the angular magnification of the telescope.
Given that,
distance = 25cm
focal length from the objective f₀ = 20cm
focal length from eye piece f₁ = 5cm
The angular magnification of the telescope is
Magnification = 20 / 5
magnification = 4
Hence, the magnitude of the angular magnification of the telescope. is 4
Answer:
speed of masses after collision = 2m/s
Explanation:
Using the formula for inelastic collision;
m1u1 + m2u2 = (m1+m2)v
Where m1 is mass of body 1
m2 is mass of body 2
u1 is initial velocity of body 1
u2 is initial velocity of body 2
v is final velocity
m1 =2kg , u1=5m/s , m2=3kg, u2=0(body at rest) v=?
(2*5) + (3*0)= (2+3)v
10=5v
v = 10/5
v=2m/s
Answer:
A the one that was thrown
B the one that was thrown
C the one that was just dropped
Explanation:
pl give brainliest
26.10 N is the vertical component of the force.
Rx represents the Horizontal component of force
Ry represents The Vertical component of force
According to the given diagram
Rx - Tcosθ = 0
Rx = Tcosθ
And,
Ry + Tsinθ = mg
Ry = mg - Tsinθ
The horizontal component of force =The Vertical component of force
Rx = Ry
Tcosθ = mg - Tsinθ
T(cosθ + sinθ) = 29 × 9.8 = 284.2 N
T√2 cosθ = 284.2 N
T × √2 ×0.544 = 284.2 N
T × 0.769 = 284.2 N
T = 370 N (app)
So,
Ry = 284.2 - 370 (sin 57°)
= 284.2 - 310.3 = -26.10 N
Hence, 26.10 N is the vertical component of the force exerted.
Learn more about the horizontal and vertical components here
brainly.com/question/25854506
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If the ground is flat, and there is no wind, and there are no other influences
to mess up the behavior of gravity, then you always get the maximum range
from a shot launched 45 degrees above the horizon. That means half-way
between level and straight up.