All categories

3 years ago

PLZ HELP ASAP WILL GIVE BRAINLIEST!!!

Physics

2 answers:

igomit [66]3 years ago

3 0

the answer is the forth one treatment of cancer

ArbitrLikvidat [17]3 years ago

3 0

Answer:

Soft Tissue Images

Diagnosis of Diseases

Treatment of Cancer

Explanation:

Radioactive elements such as Iodine-131, Phosphorus-32 and Cobalt-60 are widely used in the medical field for various purposes. Elements such as Iodine-131 are used as tracers in diagnosis of diseases as they can be traced easily because of their radioactivity. The radioactive elements are used extensively in identifying cancerous cells and then in their extermination. Phosphorus-32 is such an element used in identifying cancerous cells as they tend to accumulate more phosphates in comparison to normal cells.

Cobalt-60 is used widely to treat cancer as it can be used to selectively target malignant tumor while minimizing the damage to adjacent healthy cells.

You might be interested in

Suppose you are standing on the edge of a dock and jump straight down. If you land on sand your stopping time is much shorter th

denis-greek [22]

Answer:

In bringing you to a halt, the sand and the water exert the same impulse on you, but the sand exerts a greater average force

Explanation:

7 0

3 years ago

What’s the power if a student does 2240j of work for 2.8 seconds

Alex787 [66]

Answer:

800 Watts

Explanation:

Power = Work/time

Working in SI units, Power = Watts, Work = Joules, Time = seconds.

Power = 2240J/2.8s = 800 Watts.

7 0

2 years ago

Energy is conventionally measured in Calories as well as in joules. One Calorie in nutrition is one kilocalorie, defined as 1 kc

Sergeeva-Olga [200]

Answer:

a) The student must run flight of stairs to lose 1.00 kg of fat 709.5 times.

b) Average power

P(w)= 1062.07 [w]

P(hp)=1.42 [hp]

c) This activity is highly unpractical, because the high amount of repetitions he has to due in order to lose, just 1 Kg of fat.

Explanation:

First, lets consider the required amount of work to move the mass of the student. (considering running stairs just as a vertical movement)

Work:

$W= F*d= m*g*d$

Where m is the mass of the student, g is gravity (9.8 m/s) and d is the total distance going up the stairs (0.15m *85steps= 12.75m )

$W= F*d= m*g*d=85* 9.8*12.75=10620.75 [J]$

Converting from Joules to Kcals:

$\frac{10620.75}{4186} =2.537 Kcal$

Now lets take into account the efficiency of the human body (20%)

2.537 ---> 20%

x ---> 100%

$x=\frac{2.537*100}{20} =12.685$

So the student is consuming 12.685 KCals each time he runs up the stairs.

Now,

1 g --> 9 Kcals

1000 g --> 9000KCals

Burning 1 g of fat, requieres 9 KCals, 1000g burns 9000KCals. So in order to burn a 1Kg of fat:

$\frac{9000Kcals}{12.685Kcals} =709.5 times$

He must run up the stairs 709.5 times, to burn 1 Kg of fat.

********************

For b) just converting units, taking into account the time lapse. (53103.75 is the 100% of the energy in joules, from converting 12.685Kcals to joules)

$Power=\frac{Joules}{Seconds} =\frac{53103.75}{50} =1062.075 [W]\\$