The question is incomplete. The complete question is :
A viscoelastic polymer that can be assumed to obey the Boltzmann superposition principle is subjected to the following deformation cycle. At a time, t = 0, a tensile stress of 20 MPa is applied instantaneously and maintained for 100 s. The stress is then removed at a rate of 0.2 MPa s−1 until the polymer is unloaded. If the creep compliance of the material is given by:
J(t) = Jo (1 - exp (-t/to))
Where,
Jo= 3m^2/ GPA
to= 200s
Determine
a) the strain after 100's (before stress is reversed)
b) the residual strain when stress falls to zero.
Answer:
a)-60GPA
b) 0
Explanation:
Given t= 0,
σ = 20Mpa
Change in σ= 0.2Mpas^-1
For creep compliance material,
J(t) = Jo (1 - exp (-t/to))
J(t) = 3 (1 - exp (-0/100))= 3m^2/Gpa
a) t= 100s
E(t)= ΔσJ (t - Jo)
= 0.2 × 3 ( 100 - 200 )
= 0.6 (-100)
= - 60 GPA
Residual strain, σ= 0
E(t)= Jσ (Jo) ∫t (t - Jo) dt
3 × 0 × 200 ∫t (t - Jo) dt
E(t) = 0
To determine the gas which has the higher initial temperature, we need an equation that would relate energy and temperature. From thermodynamics, we use the expression Energy = nCvT where n is the number of moles, Cv is the heat capacity at constant volume and T is the temperature. By evaluating the temperature of both gases we determine the which would have higher temperature.
4800 = 2.3CvT
T = 2086.96/Cv
8500 = 2.9CvT
T = 2931.03/Cv
Assuming that both gases are the same. Therefore, the value of Cv for both would be equal. So, we conclude that it is the second gas with 2.9 moles would have the higher initial temperature.
Answer:
F = M a fundamental Newton's equation
F = 3 kg * 3 m/s^2 = 9 kg m / s^2 = 9 Newtons
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If the observer is moving away from the source ((Figure)), the observed frequency can be found: λs=vTo−voTovTs=(v−vo)Tov(1fs)=(v−vo)(1fo)fo=fs(v−vov).
373 kelvin = 99.9 Celsius. Round makes it 100. 373 kelvin also equals 212 Fahrenheit so the correct answer is A.
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