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Murrr4er [49]
3 years ago
15

Two persons manage to push a motorcar of mass 1200 kg at uniform velocity along a level road, The same motorcar can be pushed by

three persons to produce an acceleration of 0.2ms². With what force does each person push the motorcar?(assume that all persons push the motorcar with same muscular force.)
PLS HELP ME FAST PLS
Physics
1 answer:
densk [106]3 years ago
8 0

Answer:

40N by each person.

Explanation:

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Help plzzz!!! I only have 10 minutes to turn in
Lostsunrise [7]
  • The mechanic did 5406 Joules of work pushing the car.

That's the energy he put into the car.  When he stops pushing, all the energy he put into the car is now the car's kinetic energy.

  • Kinetic energy = (1/2) (mass) (speed²)

And there we have it

  • The car's mass is 3,600 kg.
  • Its speed is 'v' m/s .
  • (1/2) (mass) (v²) =  5,406 Joules

(1/2) (3600 kg) (v²) = 5406 joules

1800 kg (v²) = 5406 joules

v² = (5406 joules) / (1800 kg)

v² = (5406/1800) (joules/kg)

= = = = = This section is just to work out the units of the answer:

  • v² = (5406/1800) (Newton-meter/kg)
  • v² = (5406/1800) (kg-m²/s²  /  kg)
  • v² = (5406/1800)  (m²/s²)

= = = = =

v = √(5406/1800)  m/s

<em>v = 1.733 m/s</em>

4 0
3 years ago
A kayakeris paddling 2.50 m/s at an angle of 45° (northeast) and the current is moving 1.25 m/s at an angle of 315° (southeast).
PIT_PIT [208]

The kayaker has velocity vector

<em>v</em> = (2.50 m/s) (cos(45º) <em>i</em> + sin(45º) <em>j</em> )

<em>v</em> ≈ (1.77 m/s) (<em>i</em> + <em>j</em> )

and the current has velocity vector

<em>w</em> = (1.25 m/s) (cos(315º) <em>i</em> + sin(315º) <em>j</em> )

<em>w</em> ≈ (0.884 m/s) (<em>i</em> - <em>j</em> )

The kayaker's total velocity is the sum of these:

<em>v</em> + <em>w</em> ≈ (2.65 m/s) <em>i</em> + (0.884 m/s) <em>j</em>

That is, the kayaker has a velocity of about ||<em>v</em> + <em>w</em>|| ≈ 2.80 m/s in a direction <em>θ</em> such that

tan(<em>θ</em>) = (0.884 m/s) / (2.65 m/s)   →   <em>θ</em> ≈ 18.4º

or about 18.4º north of east.

5 0
3 years ago
Define the term mid-ocean ridge in simple, easy-to-understand words. Thanks :)
Likurg_2 [28]
According to wikipedia <em>a mid-ocean ridge is an underwater mountains system formed by tectonic plates.

</em>Happy studying!<em>
</em>
6 0
3 years ago
An object is placed on the axis of a converging mirror of focal length 200mm. The image produced is inverterd and has a magnific
sp2606 [1]

Answer:1.7 is the answer

Explanation:im smart

6 0
3 years ago
A car was traveling at a velocity of 8 m/s and then accelerated at a rate of 5 m/sr^2, reaching a velocity of 85 m/s. How far di
juin [17]

Answer:

716.1 m

Explanation:

A car was travelling at a velocity of 8m/s

It accelerated at 5m/s^2

It finally reached a velocity of 85m/s

The distance can be calculated by applying the fourth equation of motion

V^2= U^2 +2as

V= 85m/s

U= 8m/s

a= 5m/s^2

85^2= 8^2 + 2(5)(s)

7225= 64 + 10s

7225-64= 10s

7161=10s

s= 7161/10

= 716.1 m

Hence the car travelled at a distance of 716.1 m

5 0
3 years ago
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