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QveST [7]
3 years ago
12

Using the distributive property what will you do?

Mathematics
1 answer:
Art [367]3 years ago
5 0

Answer:

Rewrite expressions!

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Frank and Gregory leave Centreville traveling in opposite directions on a straight road. Gregory drives 22 miles per hour faster
Flauer [41]

Answer:

<h2>Frank speed = 37mi/h</h2><h2>Gregory speed = 59mi/hr</h2>

Step-by-step explanation:

Let the speed of Frank be x and speed of Gregory be y. If Gregory drives 22 miles per hour faster than Frank, then y = 22+x. SInce they they are 216miles apart after 2.25 hours,

Speed = Distance/Time

Total time travelled by them = 2.25hours

Total distance = 216 hours

Total speed = x+y = x+22+x

Substituting this parameters into the formula given to get x we will have;

x+22+x = 216/2.25

2x+22 = 96

2x = 96-22

2x = 74

x = 74/2

x = 37

<em>Hence the speed of Frank is 37miles per hour while that of gregory is 37+22 = 59miles/hour</em>

5 0
4 years ago
Please help explain the steps
marusya05 [52]

Answer:

the factored equation is ((x^3) +  3x^2) +  2x  = 0

Step-by-step explanation:

*The ^ means to the power of.

so you should start off by splitting it into ways, like isolate 2x and start with x^3 and 3x^2, if thats the wrong answer u are not looking for then the other formula is x^3 + 3x^2 + 2x  =   x • (x^2 + 3x + 2), again just splitting it into ways. since we know the equation is = to 0, we put 2 of them together, and since you can divide everything by x and just put x outside to keep it the same, it would become x^3 + 3x^2 + 2x  =   x • (x^2 + 3x + 2).

Your Welcome

6 0
4 years ago
I need the answer quiz ends tomorrow in 1 minute plzz
salantis [7]
Hope this helps!
Regards,
ArmyCee:)

4 0
3 years ago
Trig question -- please help if you can!
yanalaym [24]
\bf \textit{Sum and Difference Identities}&#10;\\\\&#10;sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)&#10;\\\\&#10;cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta)\\\\&#10;-------------------------------\\\\&#10;y=r[cos(\theta +R)]\implies y=r[cos(\theta )cos(R)-sin(\theta )sin(R)]&#10;\\\\\\&#10;y=rcos(\theta )cos(R)-rsin(\theta )sin(R)&#10;\\\\\\&#10;z=r[sin(\theta +R)]\implies y=r[sin(\theta )cos(R)+cos(\theta )sin(R)]&#10;\\\\\\&#10;z=rsin(\theta )cos(R)+rcos(\theta )sin(R)
4 0
4 years ago
5x-6=2x+9 solve and Check the solution
pickupchik [31]

Answer:

x = 5

Step-by-step explanation:

Take your starting equation:

5x - 6 = 2x + 9

Your first step should be to isolate the variable, X, by having it on only one side of the equation. This can be done by subtracting one of the X values (either 5x or 2x) from either side, but I recommend the side with 2x since it's a smaller value and won't result in a negative.

(This is the right side of the equation)

2x + 9

- 2x

= 9

We need to do the same thing on the other side of the equation too, to balance both sides:

(This is the left side of the equation)

5x - 6

- 2x

= 3x - 6

This is our equation now:

3x - 6 = 9

The next step is to isolate X further by removing any constants (regular numbers) from the side with X. Since the constant on that side is -6, we need to add 6 to that side so that it's cancelled out, and do the same on the other side to balance.

(This is the left side of the equation)

3x - 6

+ 6

= 3x

And now for the other side:

(This is the right side of the equation)

9

+ 6

= 15

This is our current equation:

3x = 15

The final step is to get X completely isolated. X is being multiplied by 3, so we need to divide both sides of the equation by 3 to finally get the value of X.

(This is the left side of the equation)

3x

÷ 3

= x

And now for the other side:

(This is the right side of the equation)

15

÷ 3

= 5

Our final equation:

x = 5

We can check our answer by taking the final X value, 5, and inserting it into our beginning equation.

This is the beginning equation, as a reminder:

5x - 6 = 2x + 9

Replace all instances of X with its value, 5:

(5 · 5) - 6 = (2 · 5) + 9

After simplifying, the result is:

19 = 19, which means the X value is correct.

4 0
1 year ago
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