Answer:
976.8 g
Explanation:
C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂0 ------------(1)
number of moles of reaction 1 can be shown as;
1 : 8 → 5 : 6
thus, 5 moles of CO₂ will form from the combustion of 1 mole of C₅H₁₂
molecular weight of CO₂ = 44 g/mol
molecular weight of C₅H₁₂ = 72 g/mol
mass of C₅H₁₂ = 320 g
number of moles of C₅H₁₂ = mass ÷ molecular weight = 320 / 72 = 4.44 moles
thus, number of moles of CO₂ formed = 5 * 4.44 = 22.2 moles
mass of CO₂ formed = 22.2* 44 = 976.8 g
Answer:
Explanation:
A substance that produces an excess of hydroxide ion (-OH) in aqueous solution.
This is an arrhenius Base
According to the arrhenius theory, a base is a substance that combines with water to produce excess hydroxide ions, OH⁻ in an aqeous solution. Examples are :
- Sodium hydroxide NaOH
- Potassium hydroxide KOH
A substance that produces an excess of hydrogen ion (H+) in aqueous solution
This is an arrhenius Acid
An arrhenius acid is a substance that reacts with water to produce excess hydrogen ions in aqueous solutions.
Examples are;
- Hydrochloric acid HCl
- Hydroiodic acid HI
- Hydrobromic acid HBr
Answer:
The hydrogen can be gotten from the added Acid or water during "workup".
Explanation:
Basically we can say that the reaction describe in this question is a Reduction reaction because of the chemical compound called sodium borohydride. In the reaction described above we can see that there is a Reduction of ketone to alcohol by the compound; sodium borohydride.
For the reduction Reaction to occur the C-O bond must break so as to enable the formation of O-H bond and C-H bond.
So, "the reaction mixture is treated with water and H2SO4 to produce the desired alcohol", thus, the oxygen will definitely pick up the hydrogen from H2SO4 or H2O.
Answer: There are 105 grams of acetylene in the tank.
Explanation:
According to ideal gas equation:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
P = pressure of gas = 1.39 atm
V = volume of gas = 70.0 L
n = number of moles = ?
R = gas constant = ![0.0821Latm/Kmol](https://tex.z-dn.net/?f=0.0821Latm%2FKmol)
T = temperature of gas in Kelvin = ![20.0^0C=(20.0+273)K=293.0K](https://tex.z-dn.net/?f=20.0%5E0C%3D%2820.0%2B273%29K%3D293.0K)
![1.39 atm\times 70.0 L=n\times 0.0821 L atm/K mol\times 293.0K](https://tex.z-dn.net/?f=1.39%20atm%5Ctimes%2070.0%20L%3Dn%5Ctimes%200.0821%20L%20atm%2FK%20mol%5Ctimes%20293.0K)
![n=4.04](https://tex.z-dn.net/?f=n%3D4.04)
Mass of ethylene , M = Moles × Molar mass = 4.04 mole × 26 g/mol =105g
Thus there are 105 grams of acetylene in the tank.
We'll make this a bit simpler.
1 mile = 1.60934km
90.0 million miles.
9.0 x 10^7 miles * (1.60934km / 1 mile) * (1000m / 1km) = 7.70x10^79 m