The answer is ultraviolet
Answer:
Mass of lava is 8370 g.
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Symbol:
The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.
Given data:
density of lava = 3.1 g/cm³
volume= 2700 cm³
mass= ?
Solution:
d = m/v
m = d×v
m = 3.1 g/cm³×2700 cm³
m = 8370 g
Answer:
0.062J
Explanation:
Given parameters:
Height of raising the spoon = 21cm
Mass of spoon = 30g
Unknown:
Gravitational potential energy = ?
Solution:
The gravitational potential energy of a body is the energy by virtue of the position of a such a body in space.
It is given as:
G. P. E = mgh
where m is the mass
g is the acceleration due to gravity
h is the height
Convert the parameters to appropriate units.
21cm to m gives 0.21m
30g to kg gives 0.03kg
G.P.E = 0.03 x 9.8 x 0.21 = 0.062J
Answer:
Molar concentration of S₂ is 1.77×10⁻⁶M
Explanation:
For the reaction:
2H₂S(g) ⇄ 2H₂(g) + S₂(g)
The equilibirum constant, K, is defined as:
![K = \frac{[S_2][H_2]^2}{[H_2S]^2}](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BS_2%5D%5BH_2%5D%5E2%7D%7B%5BH_2S%5D%5E2%7D)
<em>(1)</em>
Concentrations in equilibirum are:
[H₂S] : 0,163/0.500L - X
[H₂] : 0,0500/0.500L + X
[S₂] : X
Replacing the concentrations and the equilibrium value in (1):
![K = \frac{[X][0.1+X]^2}{[0326-X]^2}](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BX%5D%5B0.1%2BX%5D%5E2%7D%7B%5B0326-X%5D%5E2%7D)
1.67x10⁻⁷ = X (X² + 0.2X + 0.01) / (X² -0.652X + 0.106)
1.67x10⁻⁷X² - 1.09x10⁻⁷X + 1.77x10⁻⁸ = X³ + 0.2X² + 0.01X
0 = X³ + 0.2X² + 0.01X - 1.77x10⁻⁸
Solving for X:
X = 1.77×10⁻⁶
As [S₂] = X, <em>molar concentration of S₂ is 1.77×10⁻⁶M</em>
I hope it helps!
In order to calculate the energy required, we must first know the specific heat capacity, or the amount of energy required to raise the temperature of a unit mass of substance by 1 degree Celsius, of water. This, at 1 atm pressure, is 4.18 joules per gram.
Next, we use the formula:
Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity and ΔT is the change in temperature.
Q = 435 * 4.18 * (100 - 25)
Q = 136.4 kJ
