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Nataliya [291]
2 years ago
14

State whether the following statements are true or false mathematics.

exFormula1" title=" \geqslant" alt=" \geqslant" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Bingel [31]2 years ago
8 0

Answer:

Statements? Your question is incomplete.

dangina [55]2 years ago
4 0
Bro which statements?
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Is the product of two integers positive, negative , or zero ? How can you tell?
Firlakuza [10]

Answer:it depends on the numbers you are using.

Step-by-step explanation:

6 0
3 years ago
Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confide
ioda

Answer:

The question is incomplete, but the step-by-step procedures are given to solve the question.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{\sigma}{\sqrt{n}}

The lower end of the interval is the sample mean subtracted by M.

The upper end of the interval is the sample mean added to M.

The 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (lower end, upper end).

7 0
3 years ago
I'm so confused, pls help
Vera_Pavlovna [14]

Answer:

x = 14      D

Step-by-step explanation:

(18x + 36) / 3 = 6x + 12

6x + 12 = -16 + 8x

-6x .                -6x

12 = -16 + 2x

+16 . +16

28 = 2x

/2 .   /2

14 = x

8 0
2 years ago
a theater group made appearances in two cities. the hotel charge before tax in the second city was $1000 lower than the first. T
expeople1 [14]
I think it is 500 or 300 I really just guessed sorry
4 0
2 years ago
I need help from uh all..​
DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})

To prove this identity we will take the right side of the identity,

\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})

                         =\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})

                         =\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]

                         =\frac{1}{2}(\frac{2}{\text{tan}A} ) [Since \text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}]

                         = cot A

Hence right side of the equation is equal to the left side of the equation.

3 0
3 years ago
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