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3 years ago

14

State whether the following statements are true or false mathematics.

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2 answers:

Bingel [31]3 years ago

8 0

Answer:

Statements? Your question is incomplete.

dangina [55]3 years ago

4 0

Bro which statements?

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Is the product of two integers positive, negative , or zero ? How can you tell?

Firlakuza [10]

Answer:it depends on the numbers you are using.

Step-by-step explanation:

6 0

3 years ago

Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confide

ioda

Answer:

The question is incomplete, but the step-by-step procedures are given to solve the question.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.005 = 0.995$ , so Z = 2.575.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.575\frac{\sigma}{\sqrt{n}}$

The lower end of the interval is the sample mean subtracted by M.

The upper end of the interval is the sample mean added to M.

The 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (lower end, upper end).

7 0

3 years ago

I'm so confused, pls help

Vera_Pavlovna [14]

Answer:

x = 14 D

Step-by-step explanation:

(18x + 36) / 3 = 6x + 12

6x + 12 = -16 + 8x

-6x . -6x

12 = -16 + 2x

+16 . +16

28 = 2x

/2 . /2

14 = x

8 0

2 years ago

a theater group made appearances in two cities. the hotel charge before tax in the second city was $1000 lower than the first. T

expeople1 [14]

I think it is 500 or 300 I really just guessed sorry

4 0

2 years ago

I need help from uh all..

DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

$\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})$

To prove this identity we will take the right side of the identity,

$\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})$

$=\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})$

$=\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]$

$=\frac{1}{2}(\frac{2}{\text{tan}A} )$ [Since $\text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}$ ]

= cot A

Hence right side of the equation is equal to the left side of the equation.

3 0

3 years ago