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2 years ago

Describe some acidic oxides that can be prepared by thermal decomposition of nitrates and carbonates

Chemistry

1 answer:

azamat2 years ago

6 0

When calcium carbonate is heated, it breaks down to form calcium oxide and carbon dioxide.

Thermal decomposition is the process in which heat is required.

It is also known as thermolysis.

It is processed in which a compound breaks into two or more products when the heat is supplied.

This reaction is used for the production of oxygen.

This reaction is also used for production of acidic as well as basic oxides.

CaCO3 on thermal decomposition gives:

CaCO3→CaO+CO2

CaO→ Basic oxide.

CO2→ Acidic oxide.

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A bottle contains 3.100 ml of a liquid. the total mass of the bottle and the liquid together is 6.300 g. the mass of the empty b

Olenka [21]

The answer is <span>a. 0.665 g/m</span>

7 0

3 years ago

Read 2 more answers

I need help with balancing equations I'm doing homework and idk what to do here can you give me the answers please lol

amm1812

It's pretty easy to balance equations! Basically you want to make sure that the number of each compound is equal on both sides of the arrow.

For example number one is

Fe + H2SO4 -> Fe2(SO4)3 + H2

A 3 in front of H2SO4 because there's a subscript of 3 on the right side.

Then a 3 in front of H2 because of the previous step.

Then add a 2 in front of Fe because of the 2 subscript in Fe2(SO4)3

Then add a 1 in front of Fe2(SO4)3 because you already have an equal number of each element.

<u>2</u>Fe + <u>3</u>H2SO4 -> <u>1</u>Fe2(SO4)3 + <u>3</u>H2

I hope this explanation helps! You should really do your homework because practice is everything when it comes to chemistry. You'll need to know how to do it for exams.

3 0

2 years ago

The mode of 12, 17, 16, 14, 13, 16, 11, 14,13, 16 is

RUDIKE [14]

Answer:

<h2>Mean = 14.2</h2><h2>Median = 14</h2><h2>Mode = 16</h2><h2>Range = 6</h2>

Explanation:

__________________________________________________________

<em>Median = 14</em>

<em>Range = 6</em>

<em>Here are all the numbers from least to greatest order: 11, 12, 13, 13, 14, 14, 16, 16, 16, 17.</em>

<em>__________________________________________________________</em>

<em>Hope this helps! <3</em>

<em>__________________________________________________________</em>

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2 years ago

In the reaction 2H2O (1)+ 2Cl^- (aq)= H2(g)+Cl2 (g)+ 2OH^-(aq), which substance is reduced?

Oksanka [162]

Answer:- C. H

Explanations:- Reduction is gain of electron. In other words we could say that decrease in oxidation number is reduction.

As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.

The oxidation number in elemental form is zero.

In $H_2O$ , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in $Cl^-$ is -1. On product side, the oxidation number of hydrogen in $H_2$ is zero and in $OH^-$ the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in $Cl_2$ is 0.