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3 years ago

Peas can both cross-pollinate and self pollinate. why was this a key factor in Mandela work

1 answer:

3 0

<span>Self pollinating allowed Mendel to grow true breeding plants, and cross pollination allowed him to mix different traits and check the results</span>

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People have proposed driving motors with the earth's magnetic field. This is possible in principle, but the small field means th

fiasKO [112]

Answer:

636.619772368 A

Explanation:

$\tau$ = Torque = $1\times 10^{-3}\ N/m$

B = Magnetic field of Earth = $5\times 10^{-5}\ T$

A = Area

d = Diameter = 20 cm

Current is given by

$I=\dfrac{\tau}{BA}\\\Rightarrow I=\dfrac{1\times 10^{-3}}{5\times 10^{-5}\times \dfrac{\pi}{4}\times 0.2^2}\\\Rightarrow I=636.619772368\ A$

The current is 636.619772368 A

8 0

3 years ago

If a football player has more mass they will also have more ______ ?<br> Fill in the blank

serg [7]

If a football player has more mass, they will also have more <u>momentum</u>. This is because mass is directly proportional to momentum.

3 0

3 years ago

Reactance Frequency Dependence: Sketch a graph of the frequency dependence of a resistor, capacitor, and inductor. RLC Circuit R

jolli1 [7]

Answer:

$f=\frac{1}{2\pi \sqrt{LC}}$

Explanation:

We know that impedance of a RLC circuit is given by $Z=R+J(X_L-X_C)$

So $Z=\sqrt{R^2+(X_L-X_C)^2}$ here R is resistance $X_L$ is inductive reactance and $X_C$ is capacitive reactance

To minimize the impedance $X_L-X_C$ should be zero we know that $X_L=\omega L\ and \ X_C=\frac{1}{\omega C}$

So $\omega L-\frac{1}{\omega C}=0$

$\omega ^2=\frac{1}{LC}$

$\omega =\sqrt{\frac{1}{LC}}$

We know that $\omega =2\pi f$

So $\omega =2\pi f=\frac{1}{\sqrt{LC}}$

$f=\frac{1}{2\pi \sqrt{LC}}$

Where f is resonance frequency

8 0

3 years ago

A conductor shaped as a circular loop with a radius of 4.0 m is located in a uniform but changing magnetic field. If the maximum

bekas [8.4K]

Answer:

$\frac{\delta B}{\delta t}= 0.0995 \ T/s$

Explanation:

Given that :

The radius of the circular loop = 4.0 m

Maximum Emf $E_{max}$ = 5.0 V

The maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies can be determined via the expression;

$E_{max}$ = $Area (A) * \frac{\delta B}{\delta t}$

$E_{max}$ = $\pi r^2 * \frac{\delta B}{\delta t}$

5.0 = $\pi * (4.0)^2 * \frac{\delta B}{\delta t}$

5.0 = $50.27 * \frac{\delta B}{\delta t}$

$\frac{\delta B}{\delta t}= \frac{5}{50.27}$

$\frac{\delta B}{\delta t}= 0.0995 \ T/s$

5 0

3 years ago

How big is this restoring force compared with the tensile force stretching the spring?

madam [21]

The restoring force on the spring is found to have exactly the same magnitude as the stretching force. Option D

<h3>What is the restoring force?</h3>

The restoring force is the force that seeks to restore the spring to its equilibrium position. It has the same magnitude as the stretching force but acts in opposite direction.

Thus, the restoring force on the spring is found to have exactly the same magnitude as the stretching force.

Learn more about restoring force:brainly.com/question/12162527

#SPJ1

4 0

2 years ago