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3 years ago

Peas can both cross-pollinate and self pollinate. why was this a key factor in Mandela work

1 answer:

3 0

<span>Self pollinating allowed Mendel to grow true breeding plants, and cross pollination allowed him to mix different traits and check the results</span>

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What is your hypothesis (or hypotheses) for this experiment?

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mr or ms please type ur question fully please

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4 years ago

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Which of the following BEST describes an object velocity during free fall?

Viefleur [7K]

Objects can only go so fast and that speed is called terminal velocity. so the answer is A

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3 years ago

What do these compounds have in common H2O cl2 NH3

nasty-shy [4]

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All the compounds are covalent compounds . This means that they are formed by the sharing of pair of electrons.

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3 years ago

A storage tank containing oil (SG=0.92) is 10.0 meters high and 16.0 meters in diameter. The tank is closed, but the amount of o

blagie [28]

Answer:

a-1 Graph is attached. The relation is linear.

a-2 The corresponding height for 68 kPa Pressure is 7.54 m

a-3 The corresponding weight for 68 kPa Pressure is 1394726kg

b The original height of the column is 5.98 m

Explanation:

Part a

a-1

The graph is attached with the solution. The relation is linear as indicated by the line.

a-2

By the equation

$P=\rho \times g \times h$

Here

P is the pressure which is given as 68 kPa.
ρ is the density of the oil whose SG is 0.92. It is calculated as

$\rho=S.G \times \rho_{water}\\\rho=0.92 \times 1000 kg/m^3\\\rho=920 kg/m^3\\$

g is the gravitational constant whose value is 9.8 m/s^2
h is the height which is to be calculated

$P=\rho \times g \times h\\h=\frac{P}{\rho \times g}\\h=\frac{68 \times 10^3}{920 \times 9.8}\\h=7.54m$

So the height of column is 7.54m

a-3

By the relation of volume and density

$M=\rho \times V$

Here

ρ is the density of the oil which is 920 kg/m^3
V is the volume of cylinder with diameter 16m calculated as follows

$V=\pi r^2h\\V=3.14\times (8)^2 \times 7.54\\V=1515.23 m^3$

Mass is given as

$M=\rho \times V\\M=920 \times 1515.23\\M=1394726kg$

So the mass of oil leading to 68kPa is 1394726kg

Part b

Pressure variation is given as

$\Delta P=P_{obs}-P_{atm}\\\Delta P=115-101 kPa\\\Delta P=14 kPa\\$

Now corrected pressure is as

$P_c=P_g-\Delta P\\P_c=68-14 kPa\\P_c=54 kPa$

Finding the value of height for this corrected pressure as

$P_c=\rho \times g \times h\\h=\frac{P_c}{\rho \times g}\\h=\frac{54 \times 10^3}{920 \times 9.8}\\h=5.98m$

The original height of column is 5.98m

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4 years ago

Parallel to the handle, what is the force of friction acting on the suitcase?

mrs_skeptik [129]

<span>Lets call F the friction force which will act horizontally backwards.

As you are travelling at a constant velosity horizontally there is no overall resultant force in this direction.

ie. the force you pull with will be equal to the friction force resisting you. (you will initially have to have pulled with a greater force than the friction to get the suitcase moving)

the value of your force pulling is 60 cos26.9 (horizontally) - you should have learnt about resolving forces.

this must be equal to F

so

F=60cos26.9
F=53.5N

hope this helps you
please mark this as brainliest answer</span>

5 0

3 years ago