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algol13
3 years ago
9

Which one of these birds is an experimental population

Physics
2 answers:
natta225 [31]3 years ago
8 0
Whooping crane is the answer
kkurt [141]3 years ago
4 0

Answer Whooping Crane

An experimental population is a geologically depicted gathering of reintroduced plants or creatures that is segregated from other existing populaces of the species. It is done to protect the endangered species from getting extinct. Whooping crane is also one of those birds which were endangered and experimental population technique was used.

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A ramp with a mechanical advantage of 4 is used to move a 38-newton load. What
Evgesh-ka [11]

Explanation:

It is given that,

Mechanical advantage of a ramp is 4

It is used to move a 38 N load

We need to find the force needed to push the load up the ramp. The mechanical advantage is equal to the ratio of output force to the input force. We have output force as 38 N

So,

4=\dfrac{38}{F_i}\\\\F_i=\frac{38}{4}\\\\F_i=9.5\ N

So, the force of 9.5 N is needed to push the load up the ramp.  

3 0
3 years ago
PLEASE HELP The Hertzsprung-Russell diagram shown here suggests that the stars with BOTH the highest temperature AND greatest ab
uranmaximum [27]

Answer:

White dwarfs because you look at where the highest temperature is and where is the highest magnitude. Fun fact, the sun will become a white dwarf.

Explanation:

8 0
3 years ago
The energy of a sound wave relates to its
snow_lady [41]
The answer is B. , it will relates to its amplitude

Amplitude is the maximum extent of a vibration  or oscilation , measured from the position of equilibrium.

Hope this help you out
6 0
3 years ago
A woman is standing in the ocean, and she notices that after a wave crest passes by, five more crests pass in a time of 50.2 s.
lorasvet [3.4K]

Explanation:

(a) The period of a wave is the time required for one complete cycle. In this case, we have the time of five cycles. So:

T=\frac{t}{n}\\\\T=\frac{50.2s}{5}\\T=10.04s

(b) The frequency of a wave is inversely proportional to its period:

f=\frac{1}{T}\\f=\frac{1}{10.04s}\\f=0.01Hz

(c) The wavelength is the distance between two successive crests, so:

\lambda=30.2m

(d) The speed of a wave is defined as:

v=f\lambda\\v=(0.1Hz)(30.2m)\\v=3.02\frac{m}{s}

8 0
3 years ago
A space probe is coasting through space at a steady speed of 100p feet per second. the booster rocket fires for 1/2 seconds so t
aleksandr82 [10.1K]

Answer:

Acceleration: 9800 ft/s^2

Explanation:

The acceleration of an object is equal to the rate of change of velocity:

a=\frac{v-u}{t}

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

For the space probe in this problem, we have:

u = 100 ft/s (initial velocity)

v = 5000 ft/s (final velocity)

t = 0.5 s (time taken)

Therefore, the acceleration is

a=\frac{5000-100}{0.5}=9800 ft/s^2

6 0
3 years ago
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