1.000. An ellipse with an eccentricity of 0 is a circle.
Answer:
speed is the rate of change in distance thus it is scalar physical quantity
while velocity is the rate of change in displacement thus it is a vector physical quantity
Explanation:
vector physical quantity: is a quantity that requires both magnitude and direction to identify
scalar quantity: requires only magnitude to identify.
Answer:
Length of hole (s) = 362.77 m (Approx)
Explanation:
Given:
Time taken to hit the bottom (t) = 8.6 s
Acceleration due to gravity (g) = 9.81 m/s²
Find:
Length of hole (s) = ?
Computation:
Initial velocity (u) = 0 m/s
S = ut +1/2(gt²)
S = (0)(8.6) +1/2(9.81)(8.6)(8.6)
S = 1/2(9.81)(8.6)(8.6)
S = 1/2(9.81)(8.6)(8.6)
S = 362.7738
Length of hole (s) = 362.77 m (Approx)
Answer:
Option E is correct.
There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.
Explanation:
Normally, ignoring air resistance, for projectile motion, the range (horizontal distance teavelled) of the motion is given as
R = (u² sin 2θ)/g
where
u = initial velocity of the projectile = 20 m/s
θ = angle above the horizontal at which the projectile was launched = 30°
g = acceleration due to gravity = 9.8 m/s²
R = (30² sin 60°) ÷ 9.8
R = 78.53 m
So, Normally, the stone should travel a horizontal distance of 78.53 m. So, travelling a horizontal distance of 32 m (less than half of what the range should be without air resistance) means that, the motion of the stone was impeded, hence, option E is correct.
There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.
Hope this Helps!!!
Answer:
6.96 s
Explanation:
The period of a simple pendulum is given by:

where
L is the length of the pendulum and g the acceleration due to gravity.
In this problem, we have a pendulum with length L = 2.00 m, while the acceleration due to gravity is 1/6 that of the earth:

So, the period of the pendulum on the moon is
