1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dsp73
3 years ago
12

A chief finds a glittering stone which he shows to the family. The family assures him that the stone is pure gold but necono's.

Prepare a message of what you can do with the stones are the chief and his family the best advice.​
Physics
1 answer:
harina [27]3 years ago
3 0
<h2><u>Answer:</u></h2><h2><u>Answer:The Great Stone Face was a work of nature, formed on the perpendicular side of a mountain by some immense rocks, which had been thrown together so that, when viewed at a proper distance, they resembled the features of a human face. If the spectator approached too near, he lost the outline of the enormous face and could see only a heap of gigantic rocks, piled one upon another. But seen from a distance, the clouds clustering about it, the Great Stone Face seemed positively to be alive. It was the belief of many people that the valley owed much of its fertility to the benign face that was continually beaming over it.</u></h2><h2><u>Answer:The Great Stone Face was a work of nature, formed on the perpendicular side of a mountain by some immense rocks, which had been thrown together so that, when viewed at a proper distance, they resembled the features of a human face. If the spectator approached too near, he lost the outline of the enormous face and could see only a heap of gigantic rocks, piled one upon another. But seen from a distance, the clouds clustering about it, the Great Stone Face seemed positively to be alive. It was the belief of many people that the valley owed much of its fertility to the benign face that was continually beaming over it. </u></h2><h2><u>Answer:The Great Stone Face was a work of nature, formed on the perpendicular side of a mountain by some immense rocks, which had been thrown together so that, when viewed at a proper distance, they resembled the features of a human face. If the spectator approached too near, he lost the outline of the enormous face and could see only a heap of gigantic rocks, piled one upon another. But seen from a distance, the clouds clustering about it, the Great Stone Face seemed positively to be alive. It was the belief of many people that the valley owed much of its fertility to the benign face that was continually beaming over it. A mother and her little boy, as we said earlier, sat at the door of their cottage, gazing at the Great Stone Face and talking about it. The child’s name was Ernest.</u></h2><h2 /><h2><u>Answer:The Great Stone Face was a work of nature, formed on the perpendicular side of a mountain by some immense rocks, which had been thrown together so that, when viewed at a proper distance, they resembled the features of a human face. If the spectator approached too near, he lost the outline of the enormous face and could see only a heap of gigantic rocks, piled one upon another. But seen from a distance, the clouds clustering about it, the Great Stone Face seemed positively to be alive. It was the belief of many people that the valley owed much of its fertility to the benign face that was continually beaming over it. A mother and her little boy, as we said earlier, sat at the door of their cottage, gazing at the Great Stone Face and talking about it. The child’s name was Ernest. “Mother,” said he, while the Great Face smiled on him, “I wish that it could speak, for it looks so very kindly that its voice must indeed be pleasant. If I ever see a man with such a face, I should love him very much.”</u></h2><h2 /><h2><u>Answer:The Great Stone Face was a work of nature, formed on the perpendicular side of a mountain by some immense rocks, which had been thrown together so that, when viewed at a proper distance, they resembled the features of a human face. If the spectator approached too near, he lost the outline of the enormous face and could see only a heap of gigantic rocks, piled one upon another. But seen from a distance, the clouds clustering about it, the Great Stone Face seemed positively to be alive. It was the belief of many people that the valley owed much of its fertility to the benign face that was continually beaming over it. A mother and her little boy, as we said earlier, sat at the door of their cottage, gazing at the Great Stone Face and talking about it. The child’s name was Ernest. “Mother,” said he, while the Great Face smiled on him, “I wish that it could speak, for it looks so very kindly that its voice must indeed be pleasant. If I ever see a man with such a face, I should love him very much.” “If an old prophecy should come to pass,” answered his mother, “we may see a man some time, with exactly such a face as</u></h2>

You might be interested in
1. (30 pts) Let x(t) = cos(πt/2) be a continuous-time signal,
posledela

Given that the function of the wave is f(x) = cos(π•t/2), we have;

a. The graph of the function is attached

b. 4 units of time

c. Even

d. 4.935 J/kg

e. 1.234 W/kg

<h3>How can the factors of the wave be found?</h3>

a. Please find attached the graph of the signal created with GeoGebra

b. The period of the signal, T = 2•π/(π/2) = <u>4</u>

c. The signal is <u>even</u>, given that it is symmetrical about the y-axis

d. The energy of the signal is given by the formula;

\frac{1}{2}  \cdot  \mu^{2} \cdot \omega ^{2}  \cdot \:  {a}^{2}  \times  \lambda

Which gives;

E = 0.5 × 1.571² × 1² × 4 = <u>4.935 J/kg</u>

e. The power of the wave is given by the formula;

E = 0.5 × 1.571² × 1² × 4 × 0.25 = <u>1.234 W/</u><u>kg</u>

Learn more about waves here:

brainly.com/question/14015797

8 0
2 years ago
Find the length (in m) of an organ pipe closed at one end that produces a fundamental frequency of 494 Hz when air temperature i
elena-14-01-66 [18.8K]

Answer:

0.173 m.

Explanation:

The fundamental frequency of a closed pipe is given as

fc = v/4l .................. Equation 1

Where fc = fundamental frequency of a closed pipe, v = speed of sound  l = length of the pipe.

Making l the subject of the equation,

l = v/4fc ................ Equation 2

also

v = 331.5×0.6T ................. Equation 3

Where T = temperature in °C, T = 18.0 °c

Substitute into equation 3

v = 331.5+0.6(18)

v = 331.5+10.8

v = 342.3 m/s.

Also given: fc = 494 Hz,

Substitute into equation 2

l = 342.3/(4×494)

l = 342.3/1976

l =0.173 m.

Hence the length of the organ pipe = 0.173 m.

7 0
3 years ago
Which of these is an experiment generally regarded as being first carried out by James Joule?
Sholpan [36]
1. The correct answer among the choices provided is the third option. Measuring the temperature increase of water from doing work by stirring it is an experiment generally regarded as being first carried out by James Joule.
2.  Joule's experiment directly shows that heat is a form of energy. He wanted to make a different way of measuring energy.
8 0
3 years ago
Read 2 more answers
A billiard ball of mass m moving with speed v1=1 m/s collides head-on with a second ball of mass 2m which is at rest. What is th
Soloha48 [4]

Answer:

The velocity of mass 2m is  v_B = 0.67 m/s

Explanation:

From the question w are told that

     The mass of the billiard ball A is =m

     The initial speed  of the billiard ball A = v_1 =1 m/s

    The mass of the billiard ball B is = 2 m

    The initial speed  of the billiard ball  B = 0

Let the final speed  of the billiard ball A  = v_A

Let The finial speed  of the billiard ball  B = v_B

      According to the law of conservation of Energy

                 \frac{1}{2} m (v_1)^2 + \frac{1}{2} 2m (0) ^ 2 = \frac{1}{2} m (v_A)^2 + \frac{1}{2} 2m (v_B)^2

              Substituting values  

                \frac{1}{2} m (1)^2  = \frac{1}{2} m (v_A)^2 + \frac{1}{2} 2m (v_B)^2

Multiplying through by \frac{1}{2}m

                1 =v_A^2 + 2 v_B ^2 ---(1)

    According to the law of conservation of Momentum

            mv_1 + 2m(0) = mv_A + 2m v_B

    Substituting values

            m(1)  = mv_A + 2mv_B

Multiplying through by m

           1 = v_A + 2v_B ---(2)

making v_A subject of the equation 2

            v_A = 1 - 2v_B

Substituting this into equation 1

         (1 -2v_B)^2 + 2v_B^2 = 1

         1 - 4v_B + 4v_B^2 + 2v_B^2 =1

          6v_B^2  -4v_B +1 =1

          6v_B^2 -4v_B =0

Multiplying through by \frac{1}{v_B}

          6v_B -4 = 0

            v_B = \frac{4}{6}

            v_B = 0.67 m/s

4 0
3 years ago
The objective lens of a microscope has a focal length of 5.5mm. Part A What eyepiece focal length will give the microscope an ov
son4ous [18]

Complete Question

The distance between the objective and eyepiece lenses in a microscope is 19 cm . The objective lens has a focal length of 5.5 mm .

What eyepiece focal length will give the microscope an overall angular magnification of 300?

Answer:

The  eyepiece focal length is  f_e  = 0.027 \ m

Explanation:

From the question we are told that

    The focal length is  f_o =  5.5 \ mm =  -0.0055 \ m

This negative sign shows the the microscope is diverging light

     The  angular magnification is m = 300

     The  distance between the objective and the eyepieces lenses is  Z =  19 \ cm  = 0.19 \ m

Generally the magnification is mathematically represented as

        m  =  [\frac{Z - f_e }{f_e}] [\frac{0.25}{f_0} ]

Where f_e is the eyepiece focal length of the microscope

  Now  making f_e the subject  of the formula

         f_e  = \frac{Z}{1 - [\frac{M  *  f_o }{0.25}] }

substituting values

        f_e  = \frac{ 0.19 }{1 - [\frac{300  *  -0.0055 }{0.25}] }

         f_e  = 0.027 \ m

     

5 0
3 years ago
Other questions:
  • Which planet has the highest average surface temperature
    10·1 answer
  • Is it illegal to have earbuds in your ears while swimming at a swim meet.
    14·2 answers
  • Receiving delicious food is to escaping electric shock as ________ is to ________.
    10·1 answer
  • A steel bar that is at 10 ° c is 5 meters long, a bar for heated to 120 ° c, how long is that bar? Α = 1.2.10- ° c
    13·1 answer
  • A star has right ascension of 5 hours. Which of these statements is correct about the star?
    6·1 answer
  • When practicing deep breathing, it is best to repeat the steps for
    5·2 answers
  • The specific heat of hexane is 2.26 J/gºC. If 11,500 J of heat is added to
    12·1 answer
  • Round the following off to required number of significant figures.
    13·2 answers
  • Predict the energy transformation that occurs when carson sands a piece of wood with sandpaper.
    8·1 answer
  • What do we mean when we say that particles such as neutrinos or wimps are weakly interacting?.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!