Answer:
(a) Bus will traveled further a distance of 40 m
(b) It will take 7.5 sec to stop the bus
Explanation:
We have given initial velocity of the bus u = 24 m/sec
And final velocity v = 16 m/sec
Distance traveled in this process s = 50 m
From third equation of motion we know that 


(a) Now as the bus finally stops so final velocity v = 0 m/sec
So 

s= 90 m
So further distance traveled by bus = 90-50 =40 m
(b) Now as the bus finally stops so final velocity v= 0 m/sec
Initial velocity u = 24 m/sec
Acceleration 
So time 
Explanation:
LD₁ = 10⁵ mm⁻²
LD₂ = 10⁴mm⁻²
V = 1000 mm³
Distance = (LD)(V)
Distance₁ = (10⁵mm⁻²)(1000mm³) = 10×10⁷mm = 10×10⁴m
Distance₂ = (10⁹mm⁻²)(1000mm³) = 1×10¹² mm = 1×10⁹ m
Conversion to miles:
Distance₁ = 10×10⁴ m / 1609m = 62 miles
Distance₂ = 10×10⁹m / 1609 m = 621,504 miles.
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