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2 years ago

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A box sits on a table. A short arrow labeled F subscript N points up. A short arrow labeled F subscript g points down. A long ar

row labeled F subscript P points right. A short arrow labeled F subscript f points left. Study the force diagram to complete the sentences. The forces acting on the box are . The box will move to the

1 answer:

Aloiza [94]2 years ago

7 0

Answer:

unbalanced and right

Explanation:

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The time period T of a simple pendulum is given by the relation

Vanyuwa [196]

Answer:

$T^2 \propto L$

Explanation:

The period of a simple pendulum is given by:

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the acceleration of gravity

From this equation we can write

$T\propto \sqrt{L}\\T\propto \frac{1}{\sqrt{g}}$

Taking the square of this equation, we get:

$T^2 = (2\pi)^2 \frac{L}{g}$

So we see that $T^2$ is proportional to L and inversely proportional to g. So, we can write:

$T^2 \propto L\\T^2 \propto \frac{1}{g}$

So the only correct option is

$T^2 \propto L$

5 0

3 years ago

Read 2 more answers

2. A car traveling 300 miles in 5 hours is an example of

Tom [10]

The answer would be a speed

5 0

2 years ago

Look at figure D . Explain what will happen if a larger mass it put on the force meter

aev [14]

it will experience great force

5 0

3 years ago

g An object with mass m=2 kg is completely submerged, and tethered, to the bottom of a large body of water. If the density of th

Anit [1.1K]

Answer:

The tension in the rope is 20 N

Solution:

As per the question:

Mass of the object, M = 2 kg

Density of water, $\rho_{w} = 1000\ kg/m^{3}$

Density of the object, $\rho_{ob} = 500\kg/m^{3}$

Acceleration due to gravity, g = $10\ m/s^{2}$

Now,

From the fig.1:

'N' represents the Bouyant force and T represents tension in the rope.

Suppose, the volume of the block be V:

V = $\frac{M}{\rho_{ob}}$ (1)

Also, we know that Bouyant force is given by:

$N = \rho_{w}Vg$

Using eqn (1):

$N = \rho_{w}\frac{M}{\rho_{ob}}g$

$N = 1000\frac{2}{500}\times 10 = 40\ N$

From the fig.1:

N = Mg + T

40 = 2(10) + T

T = 40 - 20 = 20 N

$N = \rho_{w}Vg$

3 0

3 years ago

Jogging on hard surfaces with insufficiently padded shoes produces large forces in the feet and legs.

Step2247 [10]

Answer:

Part a)

$F = 15600 N$

Part b)

force is 21.2 times more than the weight of the person

Explanation:

Part a)

As it is given that the distance after which he stopped is given as

d = 1.50 cm

here finally it stops so final speed is given as

$v_f = 0$

initial speed is given as

$v_i = 6 m/s$

now by the equation of kinematics we know that

$v_f^2 - v_i^2 = 2a d$

$0^2 - 6^2 = 2(a)(0.015)$

$a = -1200 m/s^2$

Now the force on the leg is given as

$F = ma$

m = mass of leg = 13 kg

$F = (13 kg)(-1200 m/s^2)$

$F = 15600 N$

Part b)

Force due to weight of the object

$F_g = Mg$

here we know

M = 75.0 kg

$F_g = 75(9.81)$

$F_g = 735.75 N$

Now we know that the ratio of the weight with the force on leg is given as

$\frac{F}{F_g} = \frac{15600}{735.75} = 21.2 N$

so force is 21.2 times more than the weight of the person

5 0

3 years ago