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valina [46]
2 years ago
6

A box sits on a table. A short arrow labeled F subscript N points up. A short arrow labeled F subscript g points down. A long ar

row labeled F subscript P points right. A short arrow labeled F subscript f points left. Study the force diagram to complete the sentences. The forces acting on the box are . The box will move to the
Physics
1 answer:
Aloiza [94]2 years ago
7 0

Answer:

unbalanced and right

Explanation:

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The time period T of a simple pendulum is given by the relation
Vanyuwa [196]

Answer:

T^2 \propto L

Explanation:

The period of a simple pendulum is given by:

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity

From this equation we can write

T\propto \sqrt{L}\\T\propto \frac{1}{\sqrt{g}}

Taking the square of this equation, we get:

T^2 = (2\pi)^2 \frac{L}{g}

So we see that T^2 is proportional to L and inversely proportional to g. So, we can write:

T^2 \propto L\\T^2 \propto \frac{1}{g}

So the only correct option is

T^2 \propto L

5 0
3 years ago
Read 2 more answers
2. A car traveling 300 miles in 5 hours is an example of
Tom [10]
The answer would be a speed
5 0
2 years ago
Look at figure D . Explain what will happen if a larger mass it put on the force meter
aev [14]

it will experience great force

5 0
3 years ago
g An object with mass m=2 kg is completely submerged, and tethered, to the bottom of a large body of water. If the density of th
Anit [1.1K]

Answer:

The tension in the rope is 20 N

Solution:

As per the question:

Mass of the object, M = 2 kg

Density of water, \rho_{w} = 1000\ kg/m^{3}

Density of the object, \rho_{ob} = 500\kg/m^{3}

Acceleration due to gravity, g = 10\ m/s^{2}

Now,

From the fig.1:

'N' represents the Bouyant force and T represents tension in the rope.

Suppose, the volume of the block be V:

V = \frac{M}{\rho_{ob}}              (1)

Also, we know that Bouyant force is given by:

N = \rho_{w}Vg

Using eqn (1):

N = \rho_{w}\frac{M}{\rho_{ob}}g

N = 1000\frac{2}{500}\times 10 = 40\ N

From the fig.1:

N = Mg + T

40 = 2(10) + T

T = 40 - 20 = 20 N

N = \rho_{w}Vg

3 0
3 years ago
Jogging on hard surfaces with insufficiently padded shoes produces large forces in the feet and legs.
Step2247 [10]

Answer:

Part a)

F = 15600 N

Part b)

force is 21.2 times more than the weight of the person

Explanation:

Part a)

As it is given that the distance after which he stopped is given as

d = 1.50 cm

here finally it stops so final speed is given as

v_f = 0

initial speed is given as

v_i = 6 m/s

now by the equation of kinematics we know that

v_f^2 - v_i^2 = 2a d

0^2 - 6^2 = 2(a)(0.015)

a = -1200 m/s^2

Now the force on the leg is given as

F = ma

m = mass of leg = 13 kg

F = (13 kg)(-1200 m/s^2)

F = 15600 N

Part b)

Force due to weight of the object

F_g = Mg

here we know

M = 75.0 kg

F_g = 75(9.81)

F_g = 735.75 N

Now we know that the ratio of the weight with the force on leg is given as

\frac{F}{F_g} = \frac{15600}{735.75} = 21.2 N

so force is 21.2 times more than the weight of the person

5 0
3 years ago
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