Answer:
B. Increases.
Explanation:
![{ \bf{F = \frac{m {v}^{2} }{r} }} \\ { \bf{F \: \alpha \: {v}^{2} }}](https://tex.z-dn.net/?f=%7B%20%5Cbf%7BF%20%3D%20%20%5Cfrac%7Bm%20%7Bv%7D%5E%7B2%7D%20%7D%7Br%7D%20%7D%7D%20%5C%5C%20%7B%20%5Cbf%7BF%20%5C%3A%20%20%5Calpha%20%20%5C%3A%20%20%7Bv%7D%5E%7B2%7D%20%7D%7D)
Keeping mass, and radius constant, speed or velocity is directly proportioanal to centripetal force.
Answer:
Coulomb's Law states
F = K Q1 * Q2 / R^2 where K is the force constant
F2 / F1 = 2 Q1 * Q2 / (Q1 * Q2) = 2 where one of the charges is doubled
So the force will be doubled (D looks rather vague but it cannot be the other three)
Answer:
1.5 m/s/s
Explanation:
This problem can be solved using equation of motion given below
![v= u+ at](https://tex.z-dn.net/?f=v%3D%20u%2B%20at)
where v is the final velocity
u is the initial velocity
t is the time
given
final velocity = 9 m/s
initial velocity = 0 m/s
t = 6 seconds
lets substitute these value in v = u + at
9 = 0 + a*6
=> 9 = 6a
=> a = 9/6 = 3/2 = 1.5
Thus, acceleration is 1.5 m/s/s
The period of the pendulum is given by the following equation
T = 2<span>π * sqrt (L/g)
Where g is the gravity (free fall acceleration)
L is the longitude of the pendulum
T is the period.
We find g.............> (T /2</span>π)<span>^</span><span>2 = L/g
g = L/(</span>T /2π)^2...........> g = 22.657 m/s^2
Math is the process of using the given information, along with
all the general stuff that you know, to find the missing information.
With no given information, we have no way to even guess at
an answer.