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3 years ago

How many moles are in 1.5 x 10^20 molecules of NH3?

1 answer:

5 0

<span>Because the question is asking moles of NH3, the compound, any subscripts are irrelevant. It only wants to know how many moles of NH3 molecules, not individual atoms.

Therefore, we can simply convert to moles. 1.5x10^23/6.022x10^23 = .249 moles of NH3.

(If it were to ask moles of Hydrogen, for example, you would multiply the answer by 3, because there are 3 atoms of Hydrogen per one molecule of NH3. But this only asks for moles of the entire compound).

hope you have a great day! :)
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Describes how Anders Celsius devised the temperature scale that bears his name

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3 years ago

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3 years ago

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3 years ago

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3 years ago

I need helpppp

Nata [24]

Answer:

Fe₂(SO₄)₃ + 6KOH —> 3K₂SO₄ + 2Fe(OH)₃

The coefficients are: 1, 6, 3, 2

Explanation:

__Fe₂(SO₄)₃ + __KOH —> __K₂SO₄ + __Fe(OH)₃

To determine the correct coefficients, we shall balance the equation. This can be obtained as follow:

Fe₂(SO₄)₃ + KOH —> K₂SO₄ + Fe(OH)₃

There are 2 atoms of Fe on the left side and 1 atom on the right side. It can be balance by writing 2 before Fe(OH)₃ as shown below:

Fe₂(SO₄)₃ + KOH —> K₂SO₄ + 2Fe(OH)₃

There are 6 atoms of OH on the right side and 1 atom on the left side. It can be balance by writing 6 before KOH as shown below:

Fe₂(SO₄)₃ + 6KOH —> K₂SO₄ + 2Fe(OH)₃

There are 6 atoms of K on the left side and 2 atoms on the right side. It can be balance by writing 3 before K₂SO₄ as shown below:

Fe₂(SO₄)₃ + 6KOH —> 3K₂SO₄ + 2Fe(OH)₃

Now, the equation is balanced.

Therefore, the coefficients are: 1, 6, 3, 2

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2 years ago