Answer:
The ΔG° is 29 kJ and the reaction is favored towards reactant.
Explanation:
Based on the given information, the ΔH°rxn or enthalpy change is 41.2 kJ, the ΔS°rxn or change in entropy is 42.1 J/K or 42.1 * 10⁻³ kJ/K. The temperature given is 289 K. Now the Gibbs Free energy change can be calculated by using the formula,
ΔG° = ΔH°rxn - TΔS°rxn
= 41.2 kJ - 289 K × 42.1 × 10⁻³ kJ/K
= 41.2 kJ - 12.2 kJ
= 29 kJ
As ΔG° of the reaction is positive, therefore, the reaction is favored towards reactant.
Answer:
Q = 10.8 KJ
Explanation:
Given data:
Mass of Al= 100g
Initial temperature = 30°C
Final temperature = 150°C
Heat required = ?
Solution:
Specific heat of Al = 0.90 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 150°C - 30°C
ΔT = 120°C
Q = 100g×0.90 J/g.°C× 120°C
Q = 10800 J (10800j×1KJ/1000 j)
Q = 10.8 KJ
Answer:
A chemical bond is defined as the force which helps to bind more than two atoms in a molecule. There are different types of chemical bonding are present in molecules such as:
1) Ionic bonding: Because of the transfer of electrons it is present in ionic compounds. BaS is an example of ionic bonding which is containing some covalent character.
2) Covenant bonding: Because of the sharing of electrons it forms molecules. Rubber is the example of covalent bonding with some van der walls.
3) Metallic bonding: In the free state it is present in atoms of metal such as Brass is a good example of a metallic bonding because it is a metal alloy.
4) Van der walls bonding: In atoms, It includes repulsion and attraction. Solid xenon is the example of Van der wall bonding because it is an inert gas.
Answer:
Physical change is different in appearance while chemical change causes a new substance to form.
Explanation:
Hope this helps! :)
