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3 years ago

How does particles of substance behave at its melting point?

2 answers:

7 0

<span>Answer: The particles of the substace move away from each other and slip breaking the crystalline structure.
</span>
<span /><span /><span>
Explanation:
</span><span />

<span>Melting is the change of phase from solid to liquid.
</span><span />

<span>Melting is the result of adding heat to the solid.
</span><span />

<span>The particles in a solid are arranged in fixed structures, called lattices, in which the partilces are packed closed together to each other, and so they cannot move one respect to others.
</span><span />

<span>At the melting point, as heated is added, the partilcles vibrate and move more rapidly, gaining kinetic energy.
</span><span>
</span><span>
</span><span>The kinetic energy gained by the heat transferred is not used to increase the temperature but to increase the speed of the particles which finally manage to slip out of the fixed structure and so become liquid.</span>

ivolga24 [154]3 years ago

5 0

<span>When a substance is heated, its atoms gain energy and begin to vibrate rapidly within the lattice of the substance (the substance expands). As more heating continues, the atoms gain even more energy and move more rapidly until they are able to overcome the force of the bonds, that hold the atoms together in the lattice, until the structure is disrupted. </span>

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Digiron [165]

Species shown in bold are precipitates.

Ca(NO₃)₂ + 2 KOH → Ca(OH)₂ + 2 KNO₃
Ca(NO₃)₂ + Na₂C₂O₄ → CaC₂O₄ + 2 NaNO₃

Cu(NO₃)₂ + 2 KI → CuI₂ + 2 KI
Cu(NO₃)₂ + 2 KOH → Cu(OH)₂ + 2 KNO₃
Cu(NO₃)₂ + Na₂C₂O₄ → CuC₂O₄ + 2 NaNO₃

Ni(NO₃)₂ + 2 KOH → Ni(OH)₂ + 2 KNO₃
Ni(NO₃)₂ + Na₂C₂O₄ → NiC₂O₄ + 2 NaNO₃

Zn(NO₃)₂ + 2 KOH → Zn(OH)₂ + 2 KNO₃
Zn(NO₃)₂ + Na₂C₂O₄ → ZnC₂O₄ + 2 NaNO₃

A double replacement reaction takes place only if it reduces in the concentration of ions in the solution. For example, the reaction between Ca(NO₃)₂ and KOH produces Ca(OH)₂. Ca(OH)₂ barely dissolves. The reaction has removed Ca²⁺ and OH⁻ ions from the solution.

Some of the reactions lead to neither precipitates nor gases. They will not take place since they are not energetically favored.

Compare the first and last row:

Both Ca(NO₃)₂ and Zn(NO₃)₂ react with KOH. However, between the two precipitates formed, Ca(OH)₂ is more soluble than Zn(OH)₂.

As a result, add the same amount of KOH to two Ca(NO₃)₂ and Zn(NO₃)₂ of equal concentration. The solution that end up with more precipitate shall belong to Zn(NO₃)₂.

Compare the second and third row:

Cu(NO₃)₂ reacts with KI, but Ni(NO₃)₂ does not. Thus, add equal amount of KI to the two unknowns. The solution that forms precipitate shall belong to Cu(NO₃)₂.

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anyanavicka [17]

Answer:

Here's what I find.

Explanation:

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