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lara31 [8.8K]
3 years ago
8

What are the differences and similarities of physical and chemical changes?

Physics
2 answers:
puteri [66]3 years ago
5 0

Answer:

A physical can be changed back to its original state. A chemical can not.

Explanation:

yaroslaw [1]3 years ago
3 0

Answer:

Physical and chemical changes are similar because matter experiences a change in state. Physical changes are different because matter remains the same substance, just in a different state, whereas chemical changes change the matter

Explanation:

copied from the internet

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Unpolarized light whose intensity is 1.46 W/m2 is incident on the polarizer in the drawing. (a) What is the intensity of the lig
Serhud [2]

Answer:

0.73 W/m²

0.2522 W/m²

Explanation:

I_0 = Unpolarized light = 1.46 W/m²

\theta = Analyzer angle = 54°

Light through first filter

I_1=\frac{I_0}{2}\\\Rightarrow I_1=\frac{1.46}{2}\\\Rightarrow I_1=0.73\ W/m^2

The intensity of the light leaving the polarizer is 0.73 W/m²

After passing through analyzer

I=I_1cos^2\theta\\\Rightarrow I=0.73\times cos^2(54)\\\Rightarrow I=0.2522\ W/m^2

The intensity of the light that reaches the photocell is 0.2522 W/m²

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3 years ago
When observing a group of children at a daycare center, Emily made the following observations: Five year old children played in
konstantin123 [22]
This question is not about physics science.

The answer is: option <span>a. Five-year-old children have longer attention spans than three-year-old children.

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3 years ago
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You are working as an expert witness for an attorney who is suing a shipping company. The company operates ships that carry crud
AnnZ [28]

Answer:

56.7 m³

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You can find the area covered by the spill by applying the formula for area of a circular surface

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3 0
3 years ago
CAN YOU PLS CHECK IF ITS CORRECT I'LL MARK YOU BRAINLIST
Alexus [3.1K]

i think it looks good

yea it correct

BTW yw if it's right

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3 years ago
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A raindrop falls to the ground from a rain cloud at an altitude of 3000 meters.
shutvik [7]

Assuming the raindrop was stationary relative to the vertical distance to the ground at the start:

D=0.5at where d is distance, a is acceleration and t is time

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d= 0.5at+v0t

and

v=at+v0

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