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Lorico [155]
3 years ago
7

You leave the doctor's office after your annual checkup and recall that you weighed 688 N in her office. You then get into an el

evator that, conveniently, has a scale. Find the magnitude and direction of the elevator's acceleration if the scale reads
Find the magnitude of the elevator's acceleration if the scale reads 726 N
Find the direction of the elevator's acceleration if the scale reads 726 N
Find the magnitude of the elevator's acceleration if the scale reads 598 N
Find the direction of the elevator's acceleration if the scale reads 598 N
Physics
2 answers:
Lapatulllka [165]3 years ago
7 0

Answer:

a=0.5418\ m.s^{-2} upwards

a=1.283\ m.s^{-2} downwards

Explanation:

Given:

weight of the person, w=688\ N

So, the mass of the person:

m=\frac{w}{g}

m=\frac{688}{9.81}

m=70.132\ kg

  • Now if the apparent weight in the elevator, w_a= 726\ N

<u>Then the difference between the two weights is :</u>

\Delta w=w_a-w

\Delta w=726-688

\Delta w=38\ N is the force that acts on the body which generates the acceleration.

Now the corresponding acceleration:

a=\frac{\Delta w}{m}

a=\frac{38}{70.132}

a=0.5418\ m.s^{-2} upwards, because the normal reaction that due to the weight of the body is increased here.

  • Now if the apparent weight in the elevator, w_a= 598\ N

<u>Then the difference between the two weights is :</u>

\Delta w=w-w_a

\Delta w=688-598

\Delta w=90\ N is the force that acts on the body which generates the acceleration.

Now the corresponding acceleration:

a=\frac{\Delta w}{m}

a=\frac{90}{70.132}

a=1.283\ m.s^{-2} downwards, because the normal reaction that due to the weight of the body is decreased here.

Julli [10]3 years ago
5 0

Answer with Explanation:

We are given that

Weight of person=w=688 N

a.Scale reading=n=726 N

m=\frac{w}{g}=\frac{688}{9.8} m

By using g=9.8m/s^2

Net force=ma=n-w

a=\frac{n-w}{m}=\frac{726-688}{\frac{688}{9.8}}m/s^2

a=0.54 m/s^2

The sign of acceleration(a) is positive.Therefore, the direction of elevator's accelerating is upwards.

b.Scale reading=n=598 N

a=\frac{598-688}{\frac{688}{9.8}}=-1.28m/s^2

a=-1.28 m/s^2

The sign of acceleration(a) is negative.Therefore, the direction of elevator's accelerating is downwards.

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A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º. What is the coefficient of
Alex_Xolod [135]

Given :

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mg\ cos\ \theta =  120\times 10 \times cos\ 47^\circ{}=818.40 \ N

Since, box is on the verge of slipping :

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A pelican flying along a horizontal path drops
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Answer:

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