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fgiga [73]
3 years ago
12

A 36-cm-circumference loop of wire is placed between the poles of an electromagnet. When a field of 0.76 T is switched on in a t

ime of 25 ms, a current of 1.20 A is induced in the loop. What is the resistance of the loop of wire

Physics
2 answers:
nadya68 [22]3 years ago
8 0

Explanation:

Below is an attachment containing the solution.

Marrrta [24]3 years ago
5 0

Answer:

R = 25.3ohms

Explanation:

See attachment below.

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When describing electromagnetic radiation, there is a(n) _____________ relationship between wavelength and frequency and the gre
disa [49]

Its actually C. I did the question on USA test prep and it said the correct answer was C.


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Which of the following is an example of changing momentum?!
ExtremeBDS [4]

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B!!!

Explanation:

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3 years ago
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What must be the pressure difference between the two ends of a 2.6 km section of pipe, 36 cm in diameter, if it is to transport
ad-work [718]

Answer: 1.13(10)^{3} Pa

Explanation:

This problem can be solved by the following equation:

\Delta P=\frac{8 \eta L Q}{\pi r^{4}}

Where:

\Delta P is the pressure difference between the two ends of the pipe

\eta=0.20 Pa.s is the viscosity of oil

L=2.6 km=2600 m is the length of the pipe

Q=900 \frac{cm^{3}}{s} \frac{1 m^{3}}{(100 cm)^{3}}=0.0009 \frac{m^{3}}{s} is the Rate of flow of the fluid

d=36 cm=0.36 m is the diameter of the pipe

r=\frac{d}{2}=0.18 m is the radius of the pipe

Soving for \Delta P:

\Delta P=\frac{8 (0.20 Pa.s)(2600 m)(0.0009 \frac{m^{3}}{s})}{\pi (0.18 m)^{4}}

Finally:

\Delta P=1135.26 Pa \approx 1.13(10)^{3} Pa

7 0
3 years ago
An astronaut, of total mass 86.0 kg including her suit, stands on a spherical satellite of mass 360 kg, both at rest relative a
Afina-wow [57]

Answer: 0.56 m/s

Explanation:

Hi, to answer this question we have to apply the formula of the conservation of momentum.

m1 v1 = m2 v2 (because the system is stationary at the beginning)

Where:

m1 = mass of the astronaut

v1= velocity of the astronaut

m2= mass of the satellite

v2= velocity of the satellite

Replacing with the values given and solving:

86 kg (2.35m/s) = 360 kg v2

202.1 kgm/s=360kg v2

202.1kgm/s /360kg =v2

v2 = 0.56 m/s

Feel free to ask for more if needed or if you did not understand something.

5 0
3 years ago
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