A 36-cm-circumference loop of wire is placed between the poles of an electromagnet. When a field of 0.76 T is switched on in a t
ime of 25 ms, a current of 1.20 A is induced in the loop. What is the resistance of the loop of wire
2 answers:
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Answer:
2.58 m/s
Explanation:
We can use the following equation of motion to find out the constant acceleration of the block:
where v = 3.8 m/s is the final velocity after it has traveled 7.4 m, is the initial velocity of the block when it starts from rest, , and
is the distance traveled.
We can use the same motion equation to calculate block speed at the end of 3.4m track
Answer:
The period would decrease by sqrt(2)
Explanation:
The restoring force is given by,
F = -kx
According to Newton's second law of motion,
ma = -kx
ma + kx = 0
The time period is given by,
T =
Where is the angular velocity and it is given by,
=
Now if the spring constant is doubled then,
Thus,
=
Thus, The period would decrease by sqrt(2).
Hence, option D is correct.