A risk-free, zero-coupon bond with a $5000 face value has ten years to maturity. The bond currently trades at $3650. What is the
1 answer:
Answer:
The Yield to Maturity of the bond is YTM = 3.20%
Explanation:
Mathematically the Yield to Maturity of the bond YTM is as follows
Where C is the amount of payment to be made = $0
P is the price i.e the present value =$3650
F is the face value of the bond=$5000
n is the year of maturity of the bond = 10 years
%
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Answer:
A) - 1.8 m/s
Explanation:
As we know that whole system is initially at rest and there is no external force on this system
So total momentum of the system must be conserved
so we will have
now plug in all data into above equation
so correct answer is
A) - 1.8 m/s
The car’s velocity at the end of this distance is <em>18.17 m/s.</em>
Given the following data:
- Initial velocity, U = 22 m/s
- Deceleration, d = 1.4
- Distance, S = 110 meters
To find the car’s velocity at the end of this distance, we would use the third equation of motion;
Mathematically, the third equation of motion is calculated by using the formula;
Substituting the values into the formula, we have;
<em>Final velocity, V = 18.17 m/s</em>
Therefore, the car’s velocity at the end of this distance is <em>18.17 m/s.</em>
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Answer:
1.3823 rad/s
20.7345 m/s
28.66129935 m/s²
2006.29095 N radially outward
Explanation:
r = Radius = 15 m
m = Mass of person = 70 kg
g = Acceleration due to gravity = 9.81 m/s²
Angular velocity is given by
Angular velocity is 1.3823 rad/s
Linear velocity is given by
The linear velocity is 20.7345 m/s
Centripetal acceleration is given by
The centripetal acceleration is 28.66129935 m/s²
Acceleration in terms of g
Centripetal force is given by
The centripetal force is 2006.29095 N radially outward
The torque will be experienced when the centrifuge is speeding up of slowing down i.e., when it is accelerating and decelerating.