A risk-free, zero-coupon bond with a $5000 face value has ten years to maturity. The bond currently trades at $3650. What is the
1 answer:
Answer:
The Yield to Maturity of the bond is YTM = 3.20%
Explanation:
Mathematically the Yield to Maturity of the bond YTM is as follows
Where C is the amount of payment to be made = $0
P is the price i.e the present value =$3650
F is the face value of the bond=$5000
n is the year of maturity of the bond = 10 years
%
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Answer:
i) The pressure acting on the base of <em>B</em> will be half the pressure acting on the base of <em>A</em>
ii) The pressure acting on the base of <em>B</em> will be the same as the pressure acting on the base of <em>A</em>
iii) The pressure on the base of drum <em>A</em> will be slightly less than the pressure on the base of drum <em>B</em>
Explanation:
The pressure acting on the base of the drum, P = h·ρ·g
Where;
h = The level of the liquid in the drum
= The height of the drums
ρ = The density of the liquid in the drum
g = The acceleration due to gravity ≈ 9.81 m/s²
i) If <em>A</em> is completely filled, we have =
Therefore, =
×
×g
If <em>B</em> is half filled, we have, = (1/2)·
= (1/2) ×
×
×g
Therefore, = (1/2) ×
The pressure acting on the base of <em>B</em> will be half the pressure acting on the base of <em>A</em>
ii) If both <em>A</em> and <em>B</em> are each filled with water (the same liquid), then the pressure on their bases will be =
×
×g =
, the same, given that the acceleration due to gravity, <em>g</em>, is constant and the same in Nepal and India
iii) If <em>A</em> is filled with water, and <em>B</em> is filled with salty water, we have that, the density of salty water is slightly higher than water, therefore, we get;
=
×
×g <
=
The pressure on the base of drum <em>A</em> will be less than the pressure on the base of drum <em>B.</em>
Answer:
Explanation:
Radius of dee, r = 8 mm = 0.008 m
Electric field, e = 400 V/m
Magnetic field, B = 4.7 x 10^-4 T
mass of electron, m = 9.1 x 10^-31 kg
charge of electron, q = 1.6 x 10^-19 C
(a) Let v is the speed of electrons.
v = 661098.9 = 661099 m/s
(b)
e / m = 1.76 x 10^14 C / kg
(c) Let K be the kinetic energy
K = 0.5 x mv²
K = 0.5 x 9.1 x 10^-31 x 661099 x 661099
K = 1.99 x 10^-19 J
K = 1.24 eV
So, the potential difference is
V = 1.24 V
(d) if the acceleration voltage is doubled
V = 2 x 1.24 = 2.48 V
So, Kinetic energy
K = 2.48 eV
K = 2.48 x 1.6 x 10^-19 = 3.968 x 10^-19 J
Let v is the speed
K = 0.5 x mv²
3.968 x 10^-19 = 0.5 x 9.1 x 10^-31 x v²
v = 933856.5 m/s
Let the new radius is r.
r = 0.0113 m = 1.13 cm
Answer:
A. True
Explanation:
When a stone is thrown straight-up, it has an initial velocity which decreases gradually as the stone move to maximum height due to constant acceleration due to gravity acting downward on the stone, at the maximum height the final velocity of the stone is zero. As the stone descends the velocity starts to increase and becomes maximum before it hits the ground.
Height of the motion is given by;
g is acceleration due to gravity which is constant
H is height traveled
u is the speed of throw, which determines the value of height traveled.
Therefore, when the stone is caught at the same height from which it was thrown in the absence of air resistance, the speed of the stone when thrown will be equal to the speed when caught.