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3 years ago

Your diagram is a muscle that helps you breathe. do you think this muscle is voluntary or involuntary? Explain.

Physics

1 answer:

PIT_PIT [208]3 years ago

3 0

The diaphragm is primarily an involuntary muscle. Although voluntary means can be achieved, such as when you hold your breath while swimming, this is temporary as the diaphragm will eventually work on its own to supply your body with oxygen.

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the intermolecular force of attraction increases when intermolecular space decreases .Is it true or false

Lerok [7]

Answer:

true

Explanation:

Have a great day/night! ^_^

4 0

2 years ago

A plane leaves the airport in Galisteo and flies 170 km at 68.0° east of north; then it changes direction to fly 230 km at 36.0°

luda_lava [24]

Answer:

The direction will be $84.86^\circ$ and the distance 250.75km.

Explanation:

Let's say A is the displacement vector which represents the first 170km and B the one for the next 230km. Then the components of these vector will be:

$A_x=170cos(68^{\circ})\\ A_y=170sin(68^\circ)\\\\B_x=230cos(-36^\circ)\\B_y=230sin(-36^\circ)$

The vector which point from the origin to the final position of the plane will be R=A+B. We sum components on <em>x </em>and <em>y </em>independetly (vector property):

$R_x=A_x+B_x=170cos(68^{\circ})+230cos(-36^\circ)=63.68km+186.07km=249.75km$

$R_y=A_y+B_y=170sin(68^\circ)+230sin(-36^\circ)=157.62km-135.19km=22.43km$

If $\theta$ is the direction of R then:

$tan(\theta )=\frac{R_x}{R_y}$ ⇒ $\theta = arctan(\frac{R_x}{R_y})$ ⇒ $\theta = 84.86^\circ$ .

The distance will be given by the magnitud of the vector R:

$R=\sqrt{R_x^2 + R_y^2}$ ⇒ $R=\sqrt{R_x^2 + R_y^2} = 250.75$ .

4 0

3 years ago

A small remote-control car with a mass of 1.65 kg moves at a constant speed of v = 12.0 m/s in a vertical circle inside a hollow

Reil [10]

Answer:

$N=63.69N$

Explanation:

The normal force exerted on the car by the walls of the cylinder at the bottom of the vertical circle will be such that when substracted to the weight it must give the centripetal force, since at that point on the vertical $F_{cp}=N-W=N-mg$

We also know that the equation for the centripetal force is:

$F_{cp}=ma_{cp}=\frac{mv^2}{r}$

Mixing both equations we get:

$N-mg=\frac{mv^2}{r}$

$N=mg+\frac{mv^2}{r}$

Which for our values means:

$N=(1.65Kg)(9.8m/s^2)+\frac{(1.65Kg)(12m/s)^2}{(5m)}=63.69N$

8 0

2 years ago

Assume that the stopping distance of a van varies directly with the square of the speed. A van traveling 40 miles per hour can s

Daniel [21]

Answer:

d = 100.8 ft

Explanation:

As we know that initial speed of the van is 40 miles then the stopping distance is given as 70 feet

here we know that

$v_f^2 - v_i^2 = 2 ad$

so here we have

$0^2 - 40^2 = 2 a (70 feet)$

now again if the speed is increased to 48 mph then let say the stopping distance is "d"

so we will have

$0^2 - 48^2 = 2 a (d)$

now divide the above two equations

$\frac{40^2}{48^2} = \frac{70 feet}{d}$

$d = 100.8 ft$

4 0

3 years ago

Number 13 please!!!!!!!!!!!

atroni [7]

'A' and 'C' both show that behavior.

'D' also shows it, but the object is moving backwards when time begins.
First it moves faster and faster backwards, then it moves slower and slower backwards.

4 0

3 years ago