Let point (x, y) be any point on the graph, than the distance between (x, y) and the focus (3, 6) is sqrt((x - 3)^2 + (y - 6)^2) and the distance between (x, y) and the directrix, y = 4 is |y - 4|
Thus sqrt((x - 3)^2 + (y - 6)^2) = |y - 4|
(x - 3)^2 + (y - 6)^2 = (y - 4)^2
x^2 - 6x + 9 + y^2 - 12y + 36 = y^2 - 8y + 16
x^2 - 6x + 29 = -8y + 12y = 4y
(x - 3)^2 + 20 = 4y
y = 1/4(x - 3)^2 + 5
Required answer is f(x) = one fourth (x - 3)^2 + 5
3.07, 3.7, 3.77, 7.3, 7.33
Answer:
Step-by-step explanation:
lope is (13000-15000)/(5-3)=-2000/2=-1000
point slope formula: y-y1=m(x-x1), m slope and (x1,y1) a point
y-15000=-1000(x-3)
y-15000=-1000x+3000
y=-1000x+18000
when x=$3.50
y=-3500+18000=14,500 noodles predicted to be sold.
Answer:
See below.
Step-by-step explanation:
So, we have:
Recall that secant is simply the reciprocal of cosine. So we can:
Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.
Therefore, the possible values for theta is
5π/6 +2nπ
and
7π/6 + 2nπ
Answer:
C: S, Q
D: 80
E: Area: 80 Perimeter: 40
F: Area: 48 Perimeter: 28
I hope this is right!!
