Answer:
- 1.67 m/s
Explanation:
mass of first ball, m = 10 kg
mass of second ball, M = 20 kg
initial velocity of first ball, u = 5 m/s
initial velocity of second ball, U = - 5 m/s (direction is opposite to the first ball)
Let the final velocity of the combined mass is V.
Use the principle of conservation of linear momentum
Momentum before collision = Momentum after collision
m u + M U = ( m + M) V
10 x 5 + 20 x (-5) = (10 + 20) x V
50 - 100 = 30 V
- 50 = 30 V
V = - 1.67 m/s
Thus, the combined mass moves in the negative x axis direction with the velocity of 1.67 m/s.
Acceleration can be found using one of the following suvat equations:

Explanation:
The acceleration of an object is defined as the rate of change of velocity of the object:

where
v is the final velocity
u is the initial velocity
t is the time taken for the velocity to change from u to t
There are several equations used to find the acceleration of an object moving in a straight line (they are usually called suvat equation). Depending on which quantities are given in the problem, you can use one of the following equations:

where
is the acceleration
is the distance covered
is the time
is the initial velocity
is the final velocity
Learn more about acceleration and suvat equations:
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Answer:
6.91 Hz
Explanation:
Volume of the cube
= (1.5 x 10⁻² )³m³
= 3.375 x 10⁻⁶ m³
mass of the cube
= 3.375 x 10⁻⁶ x 8920 ( 8.92 g / cm³ = 8920 kg/m³ )
m = 30.105 x 10⁻³ kg
Spring stretches by 2.65 x 10⁻² m due to a force of 1.5 N.
If k be the force constant
k x = F
K x2.65 x 10⁻² = 1.5
k = .566 x 10² N / m
Now frequency of oscillation for spring - mass system is given by
n = 
=
n = 6.91 Hz