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Vikki [24]
4 years ago
9

If you are measuring 25 mL of liquid in a beaker that is graduated every 1 mL, the measured volume would be

Physics
1 answer:
quester [9]4 years ago
5 0

Answer:

(25\pm 1) mL

Explanation:

We are told that the volume of liquid measured is

V = 25 mL

However, we also know that the beaker is graduated every 1 mL. This means that the sensitivity of the instrument is

\pm 1 mL

This means that we cannot measure the volume of the liquid with a precision better than this value. So, the actual measurement of the liquid volume is

(25\pm 1) mL

Or, written as interval,

(24-26)mL

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picking up a pile of books from the floor

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3 years ago
g A solid disk rotates in the horizontal plane at an angular velocity of rad/s with respect to an axis perpendicular to the disk
maksim [4K]

Complete question:

A solid disk rotates in the horizontal plane at an angular velocity of 0.067 rad/s with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.18 kg.m2. From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.40 m from the axis. The sand in the ring has a mass of 0.50 kg. After all the sand is in place, what is the angular velocity of the disk?

Answer:

The angular velocity of the disk is 0.0464 rad/s

Explanation:

Given;

initial angular velocity of disk, ωi = 0.067 rad/s

initial moment of inertia of the disk, I₁ =  0.18 kg.m²

radius of sand on the disk, R = 0.40 m

mass of sand, m = 0.50 kg

Initial angular momentum = Final angular momentum

I_i \omega_i = I_f \omega_f\\\\I_i \omega_i  = (I_{sand} + I_{disk})\omega _f

Moment of inertia of sand ring = MR²

\omega_f = \frac{I_i\omega_i}{I_{sand} +I_{disk}} = \frac{0.18*0.067}{MR^2 +0.18} \\\\\omega_f = \frac{0.18*0.067}{0.5*0.4^2 +0.18}= 0.0464 \ rad/s

Therefore, the angular velocity of the disk is 0.0464 rad/s

8 0
3 years ago
A 35 g block of ice is cooled to −83 ◦C. It is added to 565 g of water in an 87 g copper calorimeter at a temperature of 22◦C. F
Tcecarenko [31]

Answer:

Explanation:

Heat gained by ice in warming up to 0⁰C = .035 x 2090 x (83-0)= 6071.45 J

heat used up by ice to melt at 0⁰C = .035 x 3.33 x 10⁵ J = 11655 J

Heat used up in warming up water to t⁰C = .035 x 4186 x t = 146.51 t

heat released by warm water to cool from 22⁰C to t = .565 x 4186 x ( 22 - t )

=52032 -2365.1 t

heat released by copper calorimeter  to cool from 22⁰C to t =  .087 x 387 x ( 22 - t ) = 740.72 - 33.7 t

total heat released = 52032 -2365.1 t  + 740.72 - 33.7 t

= 52772.72 - 2398.8 t

Heat lost = heat gained

52772.72 J- 2398.8 t  = 6071.45 J + 11655 J + 146.51 t

2545.31 t = 35046.27

t = 13.8°C.

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How do they make pickle sunflower seeds?
Kobotan [32]

<em>Preheat oven to 350°F. Spray large baking sheet with cooking spray. </em>

<em> </em>

<em>Place dill, garlic powder, onion powder, salt, sugar and ascorbic acid in small bowl and stir to combine. </em>

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<em>Generously season sunflower seeds with dill mixture and toss to combine. Taste and season again, if needed. </em>

<em> </em>

<em>Arrange seeds on baking sheet and transfer to oven to brown for 10 to 15 minutes, tossing every 5 minutes to prevent burning. </em>

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<em>Remove from oven, let cool and store in airtight container.</em>

7 0
3 years ago
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