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zloy xaker [14]
3 years ago
10

Light can travel through a medium, but it does not require a medium. a. True b. False

Physics
1 answer:
kaheart [24]3 years ago
6 0

That's true.  Light can travel through glass, water or jello,
but it also gets here very effectively through empty space,
from the sun and stars.

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Discipline will inprove your profoments - mithbusters 
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3 years ago
At this radius, what is the magnitude of the net force that maintains circular motion exerted on the pilot by the seat belts, th
Ainat [17]

Answer:

Fc=5253 N

Explanation:

Answer:

Fc=5253 N

Explanation:

sequel to the question given, this question would have taken precedence:

"The 86.0 kg pilot does not want the centripetal acceleration to exceed 6.23 times free-fall acceleration. a) Find the minimum radius of the plane’s path. Answer in units of m."

so we derive centripetal acceleration first

ac (centripetal acceleration) = v^2/r

make r the subject of the equation

r= v^2/ac

 ac is 6.23*g which is 9.81

v is 101m/s

substituing the parameters into the equation, to get the radius

(101^2)/(6.23*9.81) = 167m

Now for part

( b) there are two forces namely, the centripetal and the weight of the pilot, but the seat is exerting the same force back due to newtons third law.

he net force that maintains circular motion exerted on the pilot by the seat belts, the friction against the seat, and so forth is the centripetal force.

Fc (Centripetal Force) = m*v^2/r  

So (86kg* 101^2)/(167) =

Fc=5253 N

4 0
4 years ago
PLEASE HURRY!!!!! Which statement describes gravity? There is no defined unit of measurement for gravity Gravity is the force th
Allushta [10]

The second statement is correct : Gravity is a force that pulls objects towards Earth's centre.

8 0
3 years ago
Assume your car reaches a speed of 21.7 m/s at a steady rate for 5.05 s after the light turns green. (a) What distance have you
boyakko [2]

Answer:

The distance and average speed are 54.79 m and 10.85 m.

Explanation:

Given that,

Speed = 21.7 m/s

Time = 5.05 s

(a). We need to calculate the distance

Firstly we will find the acceleration

Using equation of motion

v = u+at

a = \dfrac{v-u}{t}

Where, v = final velocity

u = initial velocity

t = time

Put the value in the equation

a = \dfrac{21.7-0}{5.05}

a = 4.297 m/s^2

Now, using equation of motion again

For distance,

s = ut+\dfrac{1}{2}at^2

s = 0+\dfrac{1}{2}\times4.3\times(5.05)^2

s=54.79\ m

The distance is 54.79 m.

(b). We need to calculate the average speed during this time

v_{avg}=\dfrac{D}{T}

Where, D = total distance

T = time

Put the value into the formula

v_{avg}=\dfrac{54.79}{5.05}

v_{avg}=10.85\ m/s

Hence, The distance and average speed are 54.79 m and 10.85 m.

3 0
3 years ago
What is a result of using a machine?
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6 0
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