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zloy xaker [14]
3 years ago
10

Light can travel through a medium, but it does not require a medium. a. True b. False

Physics
1 answer:
kaheart [24]3 years ago
6 0

That's true.  Light can travel through glass, water or jello,
but it also gets here very effectively through empty space,
from the sun and stars.

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URGENT WORTH 30 POINTS!!
olchik [2.2K]

Answer:

1. It won't break

2. 0.5 squared meters

Explanation:

1. Pressure (P) is force (F) exerted over an area(A). Greater the force or smaller the area, the pressure will be greater. This is presented by an equation:

P = F / A

This metallic object can be placed on the table in 3 different positions, depending on which its side is pressed against the table. Since its dimensions are 3 • 6 • 8 m, surface areas of these sides are:

A1 = 3 • 6 = 18m^2

A2 = 3 • 8 = 24m^2

A3 = 6 • 8 = 48m^2

It is already stated that the smaller are, greater the pressure, so this object will exert the greatest pressure if it's placed on the table with its 18m^2 side. In this case, pressure will be:

P = 400N / 18m^2

P = 22.2 N/m^2 (N/m^2 is the same unit as Pascal)

So, the table can withstand 250 Pa of pressure, the object exerts only 22.2 Pa, which means that the glass table won't break.

2. Again, we need to know the equation that connects the force and the pressure, and that is:

P = F / A

In this case, we have both the force and the pressure, and we want to find the surface of the area. From the previous equation, area can be found as:

A = F / P

A = 20N / 40Pa (N/m^2)

A = 0.5 m^2

So, the answer is: this pressure is exerted on the area of half of squared metar.

8 0
3 years ago
When two objects collide and stick together, what will happen to their speed, assuming momentum is conserved?
sladkih [1.3K]

Answer:

When two objects collide and stick together, what will happen to their speed, assuming momentum is conserved? They will move at the same velocity as whichever object was fastest initially. They will move at the same velocity of whichever object was slowest initially.

Explanation:

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3 years ago
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Ugo [173]

A. physical

D. Upper right

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Assuming a nearly frictionless ride, what can you say about a roller coaster’s potential and kinetic energy from the top to the
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E=K+U
where
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U=mgh is the gravitational potential energy

Since the ride is frictionless, the total mechanical energy E is conserved during the ride. Therefore, at the top of the hill, the potential energy is maximum, because h (the height) is maximum, and this means the kinetic energy is minimum (because the sum of K and U is constant), so the velocity will be minimum. Viceversa, at the bottom of the hill, the potential energy will be minimum (because h is minimum), so the kinetic energy K will be maximum, and the velocity v of the roller coaster will be maximum.
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A 225 kg red bumper car is moving at 3.0 m/s. It hits a stationary 180 kg blue bumper car. The red and blue bumper cars combine
klemol [59]
I think the answer for the question above its            b 1.2
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