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What graph would best represent acceleration as a function of mass when a constant force is applied?

Alex17521 [72]

The graphs of the acceleration as a function of mass and of the acceleration as a function of force are in attachment.

Explanation:

To answer both parts of the question, we refer to Newton's second law, which states that:

$F=ma$

where

F is the net force on an object

m is the mass of the object

a is its acceleration

a)

To answer this part, we re-arrange the previous equation as follows:

$a=\frac{F}{m}$

Therefore, we notice that if a constant force is applied, the acceleration is inversely proportional to the mass of the object:

$a \propto \frac{1}{m}$

this means that if the mass increases, the acceleration decreases, and if the mass decreases, the acceleration increases.

In a graph of acceleration vs mass, the curve representing this relationship would be a hyperbole. The graph is shown as the first graph in the attached picture.

b)

As before, we re-arrange the previous equation as follows:

$a=\frac{F}{m}$

Here we notice that if the object has a constant mass, the acceleration is directly proportional to the force applied on the object:

$a \propto F$

this means that when the force increases, the acceleration increases, and when the force decreases, the acceleration decreases.

In a graph of acceleration vs force, the curve representing this relationship would be a straight line, as shown in the second graph in the attached picture.

Learn more about Newton's second law of motion here:

brainly.com/question/3820012

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6 0

3 years ago

What is the difference between radial acceleration and tangential acceleration and how do you calculate both of these accelerati

sergey [27]

Answer:

Tangential acceleration is in the direction of velocity - along the circumference of a circle if the object is undergoing circular motion

a = (V2 - V1) / T

Radial acceleration is perpendicular to the direction of motion if the object is not moving in a straight line (perhaps along the circumference of a circle)

a = m V^2 / R = m ω^2 R where R is the radius vector of the velocity - note that the Radius vector is directed from the center of motion to the object and for circular motion would be constant in magnitude but not in direction

8 0

2 years ago

At an amusement park, the wheelie carries passengers in a circular path of radius r = 11.2 m. If the angular speed of the wheeli

Dafna1 [17]

Answer:

(a) Tangential velocity will be 38.648 m/sec

(b) Acceleration will be $133.617m/sec^2$

Explanation:

We have given radius r = 11.2 m

Angular speed $\omega =0.550rev/sec=0.550\times 2\pi =3.454rad/sec$

(a) We have to find the tangential velocity

We know that tangential velocity is given by

$v_t=\omega r=3.454\times 11.2=38.684m/sec$

(b) We know that acceleration is given by

$a=\frac{v^2}{r}=\frac{38.684^2}{11.2}=133.617m/sec^2$

8 0

3 years ago

"Calculate the speed of this sound wave by recording how much time it takes to travel 5 meters. Use the (old school) velocity eq

lianna [129]

1) sound velocity reported by you : 292.39 m /s

2) time to travel 1620m at that velocity: t = d / v = 1620 m / 292.39 m/s = 5.54 s, since the moment the sound wave started.

3) You might wanted to tell the time since you watched the lightning.

Then you can calculate the time since the lighting was generated,1620 m away from you, until you saw it, using the speed of light:

speed of light = 3*10^8 m/s => t = 1620 m / (3*10^8m/s) =0.0000054 s

Then, this time is completely neglectible, and yet the answer is 5.54 s, as calculated in the step 2.

7 0

4 years ago

A player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory

____ [38]

At the highest point in its trajectory, the ball's acceleration is zero but its velocity is not zero.

<h3>What's the velocity of the ball at the highest point of the trajectory?</h3>

At the highest point, the ball doesn't go more high. So its vertical velocity is zero.
However, the ball moves horizontal, so its horizontal component of velocity is non - zero i.e. u×cosθ.
u= initial velocity, θ= angle of projection

<h3>What's the acceleration of the ball at the highest point of projectile?</h3>

During the whole projectile motion, the earth exerts the gravitational force with a acceleration of gravity along vertical direction.
But as there's no acceleration along vertical direction, so the acceleration along vertical direction is zero.

Thus, we can conclude that the acceleration is zero and velocity is non-zero at the highest point projectile motion.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory

A- neither the ball's velocity nor its acceleration are zero.

B- the ball's acceleration points upward.

C- the ball's acceleration is zero but its velocity is not zero.

D- the ball's velocity points downward.

Learn more about the projectile motion here:

brainly.com/question/24216590

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7 0

2 years ago