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melamori03 [73]
3 years ago
7

When two objects collide and stick together, what will happen to their speed, assuming momentum is conserved?

Physics
2 answers:
sladkih [1.3K]3 years ago
7 0

Answer:

When two objects collide and stick together, what will happen to their speed, assuming momentum is conserved? They will move at the same velocity as whichever object was fastest initially. They will move at the same velocity of whichever object was slowest initially.

Explanation:

AveGali [126]3 years ago
5 0
The correct answer is that when two objects collide and stick together, BOTH objects will change speed.
If they are moving in the same direction, the faster moving object will slow down and the slower moving object will speed up.
If they are moving in opposite directions the faster will slow down and the slower one will change direction.
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A circuit consists of a 9.0 v battery connected to three resistors (52 , 17 , and 140 ) in series. (a) find the current that flo
Fudgin [204]
A) TOTAL Resistance = 41+18+120 = 179 ohms 
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Why scientists collect data about the moon?
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Which substances resist pH changes? <br> Acids<br> Hydrogen ions<br> Buffers<br> Bases
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Read 2 more answers
A metal wire breaks when its tension reaches 100 newton. If the radius and length of the wire were both doubled then it would br
serg [7]

Answer:

200 N

Explanation:

Since Young's modulus for the metal, E = σ/ε where σ = stress = F/A where F = force on metal and A = cross-sectional area, and ε = strain = e/L where e = extension of metal = change in length and L = length of metal wire.

So,  E = σ/ε = FL/eA

Now, since at break extension = e.

So making e subject of the formula, we have

e = FL/EA = FL/Eπr² where r = radius of metal wire

Now, when the radius and length are doubled, we have our extension as e' = F'L'/Eπr'² where F' = new force on metal wire, L' = new length = 2L and r' = new radius = 2r

So, e' = F'(2L)/Eπ(2r)²

e' = 2F'L/4Eπr²

e' = F'L/2Eπr²

Since at breakage, both extensions are the same, e = e'

So,  FL/Eπr² = F'L/2Eπr²

F = F'/2

F' = 2F

Since F = 100 N,

F' = 2 × 100 N = 200 N

So, If the radius and length of the wire were both doubled then it would break when the tension reached 200 Newtons.

7 0
3 years ago
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