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mrs_skeptik [129]
3 years ago
12

A 225 kg red bumper car is moving at 3.0 m/s. It hits a stationary 180 kg blue bumper car. The red and blue bumper cars combine

and hit a stationary green bumper car of mass 150 kg. The red, blue, and green bumper cars all combine.
A. 0.93 m/s
B 1.2 m/s
C 1.7 m/s
D 2.7 m/s
Physics
2 answers:
GuDViN [60]3 years ago
8 0

Answer:

B. 1.2m/s

Explanation:

as per the law of conservation of momentum,

initial momentum= final momentum

considering collision 1 : Mr * Vr + ( Mb * Vb) = ( Mr + Mb ) Vrb

where Vrb is the final velocity after 1st collision with which red and blue car moves.

therefore,  225* 3 + 0 = ( 225 + 180 ) Vrb

Vrb = 675/405

       = 1.67m/s

now collision 2 : ( Mr+ Mb) Vrb + MgVg= ( Mr+ Mg+ Mb ) V'

where V' is the total speed

675 + 0 = 555V'

V' = 675/555

   = 1.2 m/s

klemol [59]3 years ago
6 0
I think the answer for the question above its            b 1.2
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alekssr [168]

Answer:

Choice a. 1 kg, assuming that all other forces on the object (if any) are balanced.

Explanation:

By Newton's Second Law,

\displaystyle a = \frac{\Sigma F}{m},

where

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As a result,

\displaystyle m = \frac{\Sigma F}{a}.

Assume that all other forces on this object are balanced. The net force on the object will be 100\;\text{N}. The net force is constant. Acceleration should also be constant and the same as the average acceleration in the two seconds.

<h3>What is the average acceleration of this object?</h3>

\displaystyle \begin{aligned}\text{Acceleration} &= \text{Average Acceleration}=\frac{\text{Change in Velocity}}{\text{Time Taken}}\end{aligned}.

\displaystyle {a} = \frac{200\;\text{m}\cdot\text{s}^{-1}}{2\;\text{s}}=100\;\text{m}\cdot\text{s}^{-2}.

<h3>Apply Newton's Second Law to find the mass of the object.</h3>

\displaystyle m = \frac{\Sigma F}{a} = \frac{100\;\text{N}}{100\;\text{m}\cdot\text{s}^{-2}} = 1\;\text{kg}.

6 0
3 years ago
Read 2 more answers
Suppose you increase your walking speed from 7 m/s to 15 m/s in a period of 2 m. What is your acceleration?
likoan [24]

Acceleration = (change in speed) / (time for the change)

Change in speed = (end speed) - (start speed) = (15 m/s - 7 m/s) = 8 m/s

time for the change = 2 minutes = 120 seconds

Acceleration = (8 m/s) / (120 seconds)

Acceleration = 0.067 m/s²

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Answer:

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Explanation:

given data

mass = 265 g

frequency = 3.40 Hz

time t = 0 s

x = 6.20 cm

vx = - 35.0 cm/s

solution

as phase constant is express as

y = A cosФ ..............1

here A is amplitude that is = \sqrt{(\frac{v_x}{\omega })^2+y^2 }  = \sqrt{(\frac{35}{2\times \pi  \times y})^2+6.2^2 }  =  6.25 cm

put value in equation 1

6.20 = 6.25 cosФ

cosФ  = 0.992

Ф = 7.25 degree  

so the phase constant is 7.25 degree  

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melisa1 [442]
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Therefore,
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In 10 second, number of electrons are calculated as;
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4 0
3 years ago
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Sphinxa [80]

Answer:The place to go for the answer to such an easy question is the SI Brochure, the document which defines the SI and all its units.

8 0
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