All categories

3 years ago

Hi please please help me you’ll get points and I’ll give you brainliest

Physics

1 answer:

leonid [27]3 years ago

7 0

Answer:

see below

Explanation:

Question 1)

57kg to ug

$126\:Kg(\frac{1*10^{9}ug }{1kg} )\\\\=126(10^{9} )\\\\=126,000,000,000 ug$ (there are 9 zeros)

Question 2)

126lbs to N

$126lbs(\frac{4.45N}{1lb} )\\\\=126(4.45N)\\\\=506.7N$

You might be interested in

A baseball is thrown at an angle of 25 degrees, with a speed

Lana71 [14]

Answer:

vertical component = 9.7m/s

Explanation:

Vy= (23)sin25 = 9.7m/s

8 0

3 years ago

Young’s modulus is property of gas

eduard

Explanation:

Sorry but I don't Understand question

3 0

3 years ago

A disc with a mass of 1 kg moves horizontally to the right with a speed of 7 m/s on a table with negligible friction when it col

Elodia [21]

Answer:

1.6 m/s

Explanation:

First you need to find the momentums of each disc by multiplying their velocities with mass.

disc 1: 7*1= 7 kg m/s

disc 2: 1*9= 9 kg m/s

Second, you need to find the total momentum of the system by adding the momentums of each sphere.

9+7= 16 kg m/s

Because momentum is conserved, this is equal to the momentum of the composite body.

Finally, to find the composite body's velocity, divide its total momentum by its mass. This is because mass*velocity=momentum

16/10=1.6

The velocity of the composite body is 1.6 m/s.

7 0

2 years ago

HELP PLS!<br> (LOOK AT THE PICTURE)

Arturiano [62]

The answer is b !!!! Hope it helps

4 0

2 years ago

A cyclotron designed to accelerate protons has a magnetic field of magnitude 0.15 T over a region of radius 7.4 m. The charge on

klio [65]

Explanation:

It is given that,

Magnetic field, B = 0.15 T

Charge on a proton, $q=1.60218\times 10^{-19}\ C$

Mass of a proton, $m=1.67262 \times 10^{-27}\ kg$

The cyclotron frequency is given by :

$f=\dfrac{qB}{2\pi m}$

$f=\dfrac{1.60218\times 10^{-19}\ C\times 0.15\ T}{2\pi \times 1.67262 \times 10^{-27}\ kg}$

f = 2286785.40 Hz

$\omega=14368296.44\ rad/s$

$\omega=1.43\times 10^7 rad/s$

Hence, this is the required solution.

8 0

3 years ago