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3 years ago

Hi please please help me you’ll get points and I’ll give you brainliest

Physics

1 answer:

leonid [27]3 years ago

7 0

Answer:

see below

Explanation:

Question 1)

57kg to ug

$126\:Kg(\frac{1*10^{9}ug }{1kg} )\\\\=126(10^{9} )\\\\=126,000,000,000 ug$ (there are 9 zeros)

Question 2)

126lbs to N

$126lbs(\frac{4.45N}{1lb} )\\\\=126(4.45N)\\\\=506.7N$

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3 years ago

The distance between adjacent nodes in a standing wave pattern is 25.0 cm. What is the

Novay_Z [31]

Answer:

Answer:

Speed of the wave in the string will be 3.2 m/sec

Explanation:

We have given frequency in the string fixed at both ends is 80 Hz

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We know that distance between two adjacent anti nodes is equal to half of the wavelength

So \frac{\lambda }{2}=20cm

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3 years ago

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IrinaK [193]

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3 years ago

Flapping flight is very energy intensive. A wind tunnel test

steposvetlana [31]

Answer:

The metabolic power for starting flight=134.8W/kg

Explanation:

We are given that

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We know that

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3 years ago