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Oliga [24]
1 year ago
12

When two systems in contact are not at the same temperature, _____ occurs.expansionheat flowfrictionevaporation

Physics
1 answer:
Murljashka [212]1 year ago
8 0

Heat flow occurs when two systems in contact are not at the same temperature.

What is heat flow?

  • when two bodies of different temperatures are in contact, heat flow takes place.
  • Heat flows till the two bodies in contact achieve equilibrium.
  • To achieve equilibrium, heat flows from hotter bodies to colder bodies.
  • There is no heat flow after achieving the state of equilibrium because the amount of heat flow from one body to the other is the same.

For more information, please visit: brainly.com/question/11297584?referrer=searchResults

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discharge occurs when oppositely charged objects get close enough for the air between them to become electrically charged.
Wittaler [7]

Answer:

It does both. Once they get close enough the air does start to get charged, but then they eventually discharge when they touch.

Explanation:

4 0
3 years ago
Where are you likely to find the oldest oceanic crust?
Stells [14]

Answer:

it would be letter E. near oceanic ridges

Explanation:

new ocean crust is formed at the mid ocean ridges

4 0
3 years ago
Freight car A with a gross weight of 200,000 lbs is moving along the horizontal track in a switching yard at 4 mi/hr. Freight ca
zhenek [66]

Answer: a) 4.7 mi/hr.  b) 86,500 lbs. mi²/Hr²

Explanation:

As in any collision, under the assumption that no external forces exist during the very small collision time, momentum must be conserved.

If the collision is fully inelastic, both masses continue coupled each other as a single mass, with a single speed.

So, we can write the following:

p₁ = p₂ ⇒m₁.v₁ + m₂.v₂ = (m₁ + m₂). vf

Replacing by the values, and solving for vf, we get:

vf = (200,000 lbs. 4 mi/hr + 100,000 lbs. 6 mi/hr) / 300,000 lbs = 4.7 mi/hr

If the track is horizontal, this means that thre is no change in gravitational potential energy, so any loss of energy must be kinetic energy.

Before the collision, the total kinetic energy of the system was the following:

K₁ = 1/2 (m₁.v₁² + m₂.v₂²) = 3,400,000 lbs. mi² / hr²

After the collision, total kinetic energy is as follows:

K₂ = 1/2 ((m₁ + m₂) vf²) = 3,313,500 lbs. mi²/hr²

So we have an Energy loss, equal to the difference between initial kinetic energy and final kinetic energy, as follows:

DE = K₁ - K₂ = 86,500 lbs. mi² / hr²

This loss is due to the impact, and is represented by the work done by friction forces (internal) during the impact.

8 0
3 years ago
Question 2
Tju [1.3M]
B. True give me branliest
8 0
3 years ago
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How much heat is needed to raise the temperature of 7g of Water by 20° C
beks73 [17]

the answer to your question is 10.5 kJ

6 0
3 years ago
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