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mafiozo [28]
3 years ago
8

What is the motion of the negative electrons and positive atomic nuclei caused by the external field?

Physics
1 answer:
telo118 [61]3 years ago
3 0

Answer:

The negative electrons moves to the left While the positively charged current moves in the opposite direction to the right when an external field is applied.

The positive atomic nuclei remains almost motionless.

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Light travels at the speed of 186,000 miles per second. If you were to travel around the earth it would be 7.5 times in a second
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Si dejamos caer un objeto desde una gran altura, ¿será que tiene siempre la misma velocidad
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La respuesta es si.
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3 years ago
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A force of 10. N toward the right is exerted on a wooden crate initially moving to the right on a horizontal wooden floor. the c
Artyom0805 [142]

1) 5 N

The crate is initially moving, so we must calculate the force of kinetic friction, which is given by:

F_f = \mu_k mg

where

\mu_k=0.2 is the coefficient of friction between the crate (made of wood) and the floor (made of wood). The coefficient of kinetic friction between wood and wood is about 0.2.

mg=25 N is the weight of the crate

Substituting the numbers into the formula, we find

F_f=(0.2)(25 N)=5 N


2) 5 N

There are two forces acting on the crate along the horizontal direction:

- The force that pushes the crate toward the right, of magnitude F=10 N

- The force of friction, which acts in the opposite direction (so, towards the left), of magnitude F_f = 5 N

Since the two forces are in opposite directions, the net force is given by their difference:

F_{net}=F-F_f = 10 N-5 N=5 N


3) Yes

The crate is accelerating. In fact, according to Second Newton's Law:

F_{net}=ma (1)

where Fnet is the net force on the crate, m is its mass, a is its acceleration. We can immediately see that since Fnet is not zero, the acceleration is also non-zero, so the crate is accelerating.

We can even calculate the magnitude of the acceleration. In fact, the mass of the crate is given by:

m=\frac{Weight}{g}=\frac{25 N}{9.8 m/s^2}=2.55 kg

And by using (1) we find

a=\frac{F_{net}}{m}=\frac{5 N}{2.55 kg}=1.96 m/s^2


3 0
3 years ago
A merry-go-round is rotating at constant angular speed. Two children are riding the merry-go-round: Ana is riding at point A and
marysya [2.9K]

Answer:

bobby has a greater magnitude of velocity because because when angular speed is constant linear velocity is proportional to radius of the circular path

B. They both have same magnitude of angular velocity since the angular speed of the merrygoround is constant

C. Also they both have the same tangential acceleration because the angular speed is constant and tangential is zero for both of them

D. Centripetal acceleration of Bobby is greater

E.they both have the same angular acceleration because angular Speed I constant so angular acceleration is zero for both

3 0
3 years ago
- What is the total distance traveled by the car
slega [8]

*Graph is attached with the answer*

Answer:

Total distance traveled by the car is 40 m

Explanation:

It can be seen from the graph that for the first 4 second car is moving with uniform acceleration and for next 2 second it has constant velocity

So, we solved this question in 2 parts

Part 1:

               initial velocity = v₁ = 0 m/s

               final velocity = v₂ = 10 m/s

                time = t = 4 s

                acceleration = a = (v₂ - v₁)/t

                                a = 10/4 = 2.5 m/s²

Using 3rd equation of motion

                2as = v₂² - v₁²

                 2(2.5)s = 10²

                      s₁ = 100/5

                     s₁ = 20 m

Part 2:

            s₂ = v₂t

            s₂ = 10 × 2

            s₂ = 20 m

Total distance = S = s₁ + s₂

                              = 20 + 20

                          S = 40 m

7 0
3 years ago
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