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3 years ago

HURRY PLEASE ANSWER MY QUESTION!!

Mathematics

1 answer:

natta225 [31]3 years ago

6 0

Answer:

f(x) = 3.56(2.04)^x

Step-by-step explanation:

Put x as 2, to see whether the output will be close to 16.

116.4 - 42.8 ln(2) = 86.733301

2.04(3.56)^2 = 25.854144

3.56(2.04)^2 = 14.815296

-42.8 + 116.4 ln(2) = 37.882332

Put x as 3, to see whether the output will be close to 30.

116.4 - 42.8 ln(3) =69.379394

2.04(3.56)^3 = 92.040753

3.56(2.04)^3 = 30.223204

-42.8 + 116.4 ln(3) = 85.07847

Put x as 6, to see whether the output will be close to 271.

116.4 - 42.8 ln(6) = 39.712695

2.04(3.56)^6 = 4152.69615

3.56(2.04)^6 = 256.584846

-42.8 + 116.4 ln(6) = 165.760802

Put x as 7, to see whether the output will be close to 522.

116.4 - 42.8 ln(7) = 33.115046

2.04(3.56)^7 = 14783.598295

3.56(2.04)^7 = 523.433085

-42.8 + 116.4 ln(7) = 183.703941

The exponential function that models the data is f(x) = 3.56(2.04)^x.

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Select the point that is a solution to the system of inequalities

Zarrin [17]

<h2>Hello!</h2>

The answer is:

The point that is a solution to the system of inequalities is C(4,2).

To find the point that is a solution to the system of inequalities, we need to evaluate it into the given inequalities. If the point is a solution to the system of inequalities, both inequalities will be satisfied.

We are given the inequalities:

$y\leq 2x-2$

$y\leq x^{2} -3x$

So, substituting the given points into the given inequalities, we have:

- A. (2,1)

Substituting into the first inequality, we have:

$y\leq 2x-2\\\\1\leq 2*(2)-2\\\\1\leq 4-2\\\\1\leq 2$

Substituting into the second inequality, we have:

$y\leq x^{2} -3x$

$1\leq (2)^{2} -3(2)$

$1\leq 4 -6$

$1\leq -2$

Therefore, since 1 is not less or equal to -2, the point A(2,1) is not a solution to the system of inequalities.

- B. (-2,-1)

Substituting into the first inequality, we have:

$y\leq 2x-2\\\\-1\leq (-2)*(2)-2\\\\-1\leq -4-2\\\\-1\leq -6$

Substituting into the second inequality, we have:

$y\leq x^{2} -3x$

$-1\leq (-2)^{2} -3(-2)$

$-1\leq 4 +6$

$-1\leq 10$

Therefore, since -1 is not less or equal to -6, the point B(-2,-1) is not a solution to the system of inequalities.

- C. (4,2)

Substituting into the first inequality, we have:

$y\leq 2x-2\\\\2\leq (4)*(2)-2\\\\2\leq 8-2\\\\2\leq 6$

Substituting into the second inequality, we have:

$y\leq x^{2} -3x$

$2\leq (4)^{2} -3(4)$

$2\leq 16 -12$

$2\leq 4$

Therefore, since 2 is less than 6, and 2 is less than 4, the point B(4,2) is a solution to the system of inequalities.

- D(1,3)

Substituting into the first inequality, we have:

$y\leq 2x-2\\\\3\leq (1)*(2)-2\\\\3\leq 2-2\\\\3\leq 0$

Substituting into the second inequality, we have:

$y\leq x^{2} -3x$

$3\leq (1)^{2} -3(1)$

$3\leq 1 -3$

$3\leq -2$

Therefore, since 3 is not less than 0, and 3 is not less than -2, the point D(1.3) is not a solution to the system of inequalities.

Hence, the point that is a solution to the system of inequalities is C(4,2).

Have a nice day!

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Answer:

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Step-by-step explanation:

The domain of any parabola is (-∞, ∞)
The range of this parabola is [-2, ∞) because the vertex is at (-2, -2).

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S = 10 + r. Please give me a brainliest if you found this helpful:)

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Step-by-step explanation:

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Read 2 more answers

Answer please////////

BartSMP [9]

Answer:

Coordinate of B: (3, -5)

Coordinate of C: (3, 5)

Coordinate of D: (0, -1)

Step-by-step explanation:

Point A is (-2, -5).

The distance between line AB is 5 units.

The distance between line BC is 10 units.

To find the point for B, the distance is 5 units on the x axis.

The x point for point B is -2 + 5 which is 3 units. x = 3

The y point doesn't change, so the coordinate of point B is (3, -5).

___________________________________________________________

The distance between line BC is 10 units.

To find the point of C, the distance is 10 unites on the y axis.

The y point for point b is -5 + 10 which is 5 units. y = 5

The x point doesn't change, so the coordinate of point C is (3, 5).

___________________________________________________________

We find an equation for line AC. The equation is y = mx + b.

Y is any y point on the line. X is any x point on the line. M is the slope of the line. B is the y-intercept of the line.

Since D is right on the y axis, this means that the x point of D is 0.

Point C is (3, 5) and point A is (-2, -5).

We use (y2 - y1) / (x2 - x1) and substitute. Y is the y point and x is the x point.

(5 - (-5)) / (3 - (-2)) = 10 / 5 = 2

The slope of the line is 2.

With this, we get the equation of y = 2x + b

We insert one of the random x point and y point which (in this case) I choose (3, 5).

Substituting, we get -

5 = 2 * 3 + b

5 = 6 + b

b = 5 - 6

b = -1

So the y-intercept of the graph is -1 and for the graph, we get -

y = 2x - 1

D is already the line of the y-intercept, but we can make sure by inserting the x point as 0.

y = 2 * 0 - 1

y = 0 - 1

y = -1

The coordinate of point D is (0, -1).

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3 years ago