Answer:carbon number 3 of the parent chain
Explanation:
CH3CH2CH(CH3)C(CH3)2CH3.
Looking at the structural formula of the above compound, the carbon on position 3, in the parent chain is a tertiary carbon atom. The reaction in question proceeds by free radical mechanism. Hydrogen is first abstracted from the carbon atom that leads to te formation of the most stable carbocation. For this reason, hydrogen is abstracted from carbon 3 of the parent chain.
Many compunds have a terminal carbonyl
Aldehyde, Ketone, Carboxylic acid, Amide, Imide, Acid anhydride are the first that come to my mind.
Unit of M is also mole/L, where mole is the moles of solute and L is the volume of the solution. The latter is given: 158 mL or 0.158 L. So we need to find out the moles of NH4Br.
Moles of NH4Br = Mass of NH4Br/molar mass of NH4Br = 17.0g/(14+1*4+79.9)g/mol = 0.1736 mole.
So, the molarity of the solution = 0.1736mole/0.158L = 1.10 mole/L = 1.10 M
What is the exoeruent. Searched it up on google and only came up with two search results. None related to chemistry
