Ca(OH)2 is the answer for plato
150 g SO₂ = 2.36 mol SO₂
M_r = 32.06 + 2×16.00 = 32.07 + 32.00 = 64.06
Moles of SO₂ = 151 g SO₂ × [1 mol SO₂/64.06 g SO₂] = 2.36 mol SO₂
The answer to this would be d. Precipitation patterns .
SrCO3
Sr=2 charge
CO3=2 charge from polyatomic chart
Moles of Carbon dioxide : 13.5
<h3>Further explanation</h3>
Given
4.5 moles propane
Required
moles of Carbon dioxide
Solution
Reaction(Combustion of Propane) :
<em>C₃H₈(g)+5O₂(g)→3CO₂(g)+4H₂O(g)</em>
In a chemical equation, the reaction coefficient shows the mole ratio of the reacting compounds (either in reactants or products)
From the equation, mol ratio of Propane(C₃H₈) : Carbon dioxide(CO₂) : 1 : 3, so mol CO₂ :
= 3/1 x mol Propane
= 3 x 4.5 moles
= 13.5 moles
