To suck lemonade of density 1040 kg/m3 up a straw to a maximum height of 4.94 cm, what minimum gauge pressure (in atmospheres) m
ust you produce in your lungs?
2 answers:
Answer:
The minimum gauge pressure is 0.4969 atm.
Explanation:
Given that,
Density = 1040 kg/m³
Height = 4.94 cm
We need to calculate the pressure
Using formula of pressure

Where,
=density
h = height
Put the value into the formula


Pressure in atmospheres


Hence, The minimum gauge pressure is 0.4969 atm.
Answer:
Pressure, P = 503.48 Pascals
Explanation:
Given that,
Density of lemonade, 
Maximum height, 
We need to find the minimum gauge pressure produced in your lungs. The pressure exerted is given by :

P = 503.48 Pascals
So, the minimum gauge pressure is 503.48 pascals. Hence, this is the required solution.
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