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klasskru [66]
3 years ago
5

To suck lemonade of density 1040 kg/m3 up a straw to a maximum height of 4.94 cm, what minimum gauge pressure (in atmospheres) m

ust you produce in your lungs?
Physics
2 answers:
Lady bird [3.3K]3 years ago
7 0

Answer:

The minimum gauge pressure is 0.4969 atm.

Explanation:

Given that,

Density = 1040 kg/m³

Height = 4.94 cm

We need to calculate the pressure

Using formula of pressure

P_{g}=\rho g h

Where, \rho=density

h = height

Put the value into the formula

P_{g}=1040\times9.8\times4.94

P_{g}=50348.48\ Pa

Pressure in atmospheres

1\ atm =101.3\ kPa

P_{g}=\dfrac{50348.48}{101325}

P_{g}=0.4969\ atm

Hence, The minimum gauge pressure is 0.4969 atm.

m_a_m_a [10]3 years ago
3 0

Answer:

Pressure, P = 503.48 Pascals

Explanation:

Given that,

Density of lemonade, d=1040\ kg/m^3

Maximum height, h=4.94\ cm=0.0494\ m

We need to find the minimum gauge pressure produced in your lungs. The pressure exerted is given by :

P=d\times g\times h

P=1040\times 9.8\times 0.0494              

P = 503.48 Pascals    

So, the minimum gauge pressure is 503.48 pascals. Hence, this is the required solution.                      

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