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matrenka [14]
3 years ago
11

Please help

Physics
1 answer:
Aneli [31]3 years ago
5 0

Answer:

170 energy

Explanation:

I don't know the answer

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Every winter i fly to Chicago.vit takes 3 hours. what is my average speed​
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your average speed is 15 because 3hr times 5 winters is 15 hours

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The electric force between two charged balloons is 0.16 newtons. If the distance between them is doubled, what will the new forc
lara31 [8.8K]
<span>So we wan't to know what will the Coulomb force be between two charged baloons will be if we double the distance between the them and Fc=0.16N. The coulomb force between two charges is Fc=k*Q1*Q2/r^2. So we see from the equation that the magnitude of the force will be smaller as we increase the distance. So let's increase the distance from r to R=2r. If we input thai into the equation we get: Fc=k*Q1*Q2/R^2. Now: Fc=k*Q1*Q2/(2r)^2. And finally: Fc= k*Q1*Q2/4r^2. And if we factor out 1/4 we get: Fc=(1/4)*k*Q1*Q2/r^2. Now we can see that if we double the distance the magnitude of the force will be smaller for a factor of 1/4 or the magnitude of the force will be smaller 4 times. So finally the force is (1/4)*0.16N= 0.04N. So the correct answer is A. 0.04 newtons. </span>
4 0
4 years ago
Read 2 more answers
Alligators and other reptiles don't use enough metabolic energy to keep their body temperatures constant. they cool off at night
drek231 [11]
To compute for the heat, Q needed to be absorbed or released,  we need

Q = mc\Delta T

where m is the mass of the alligator, \Delta T is the change in temperature, and c is the specific heat of the alligator's body. Plugging in all the information we have,

Q = (300 kg)(3400 kJ/K)(30-25) = 5100000 J

Recall that 1 Watt = 1 J/s, thus time needed to absorb radiation from the sun is

t = \frac{Q}{W}\\ t = 4250 seconds

That means it takes 4250 seconds for the alligator to warm up to be able to absorb the radiation from the sun.

Answer: 4250 seconds



4 0
4 years ago
Two samples of water are mixed together.
Anon25 [30]
<h3><u>Answer;</u></h3>

A.75°C

<h3><u>Explanation</u>;</h3>

Let the change in temp of cold water be  x degrees,

while that of  hot water be 100 - x degrees.

Heat exchange =  mcΔt

Ice

Δt = x

m = 0.50 kg

c = 4.18 kJ/kg*°C

Hot water

Δt = 100 - x

m = 1.5 kg

c = 4.18

But;

Heat lost = heat gained

0.50 * c * x = 1.5 * c * (100 - x)          

0.50 *x = 1.5*(100 - x)                          

0.5x = 150 - 1.5x                                  

0.5x + 1.5x = 150 - 1.5x + 1.5x            

2x = 150                                              

x = <u>75° C</u>

Hence; the equilbrium temperature will be 75° C

7 0
3 years ago
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