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Vanyuwa [196]
3 years ago
15

A car is traveling in a straight path due east with a velocity of 8 meters per second. In a 10 second interval, how many meters

will the car travel? A) .80 m B) 2 m C) 18 m D) 80 m
Physics
2 answers:
34kurt3 years ago
6 0
The answer is c 18meters because if u add you get that answer hope I'm right bye
butalik [34]3 years ago
5 0

The answer is D.) 80m I just did this on Usatestprep.

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The United States and South Korean soccer teams are playing in the first round of the World Cup. An American kicks the ball, giv
garik1379 [7]

Answer:

Vf = 3.67 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f} ^{2} =v_{i} ^{2} -(2*a*x)

where:

Vf = final velocity [m/s]

Vi = initial velocity = 4.3 [m/s]

a = acceleration or desacceleration = 0.5 [m/s²]

x = distance = 5 [m]

Note: The negative sign in the above equation means that the velocity of the ball is decreasing (desacceleration).

Now replacing:

Vf² = (4.3)² - (2*0.5*5)

Vf² = 18.49 - 5

Vf² = 13.49

using the square root, we have.

Vf = 3.67 [m/s]

8 0
2 years ago
a golf ball is hit with a velocity of 30.0 m/s at an angle of 25 degrees about the horizontal. how long is the ball in the air a
Pie
Ok so use trigonometry to work out the vertical component of velocity.

sin(25) =opp/hyp
rearrange to:
30*sin(25) which equals 12.67ms^-1

now use SUVAT to get the time of flight from the vertical component,

V=U+at

Where V is velocity, U is the initial velocity, a is acceleration due to gravity or g. and t is the time.

rearranges to t= (V+u)/a

plug in some numbers and do some maths and we get 2.583s

this is the total air time of the golf ball.

now we can use Pythagoras to get the horizontal component of velocity.

30^2-12.67^2= 739.29
sqrt739.29 = 27.19ms^-1

and finally speed = distance/time

so--- 27.19ms^-1*2.583s= 70.24m

The ball makes it to the green, and the air time is 2.58s 
4 0
3 years ago
Use technology and the given confidence level and sample data to find the confidence interval for the population mean muμ. Assum
Ronch [10]

Answer:

a.  μ_{95%} = 3 ± 1.8 = [1.2,4.8]

b. The correct answer is option D. No, because the sample size is large enough.

Explanation:

a. The population mean can be determined using a confidence interval which is made up of a point estimate from a given sample and the calculation error margin. Thus:

μ_{95%} = x_±(t*s)/sqrt(n)

where:

μ_{95%} = = is the 95% confidence interval estimate

x_ = mean of the sample = 3

s = standard deviation of the sample = 5.8

n = size of the sample = 41

t = the t statistic for 95% confidence and 40 (n-1) degrees of freedom = 2.021

substituting all the variable, we have:

μ_{95%} = 3 ± (2.021*5.8)/sqrt(41) = 3 ± 1.8 = [1.2,4.8]

b. The correct answer is option D. No, because the sample size is large enough.

Using the the Central Limit Theorem which states that regardless of the distribution shape of the underlying population, a sampling distribution of size which is ≥ 30 is normally distributed.

4 0
3 years ago
explain which properties of metals make sterling silver the best material for you to create hammered earrings.
7nadin3 [17]

It is malleable

Explanation:

The property that makes metals such as sterling silver the best to create hammered earrings is their malleability.

All metals have a unique and fascinating property of being malleable. They can be carved into any of shape. When hammered they simply draw out and retain their long range ordering of their crystal lattice.

This is made possible by the presence of metallic bonding between the atoms.

  • The bulk of the physical properties of metals can be attributed the metallic bonds in them.
  • Metals have large sea of electrons in them.
  • In forming metallic bonds, there is an attraction between the positive nuclei of all the closely packed atoms in the lattice and the electron cloud jointly formed by all the atoms by loosing their outermost shell electrons.
  • Metals like silver have low ionization energy.
  • When they are hammered, they spread out the energy from the hammering.

learn more:

Metals brainly.com/question/2474874

#learnwithBrainly

8 0
3 years ago
A racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction). It hits the wall of th
zheka24 [161]

The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).

mass m  = 42g = 42/1000 = 0.042kg

initial velocity before collision u = 7 m/s

It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,

velocity after collision v = 7 m/s

To calculate the magnitude of the racquetball's change in momentum, we will use the formula below

Change in momentum = Mv - Mu

Since momentum is a vector quantity, we will consider the direction.

Change in momentum = 0.042 x 7 - ( 0.042 x - 7)

Change in momentum = 0.294 + 0.294

Change in momentum = 0.588 kgm/s

Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Learn more on momentum here: brainly.com/question/402617

5 0
2 years ago
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