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shutvik [7]
3 years ago
5

Students are experimenting with a substance that they think can be added to soil to increase the number of flowers a certain pla

nt will make. They set up 20 pots of soil, each planted with the same type of seed. They divide the pots into two groups and add 15 drops of the substance to pots in one group and only 10 drops to pots in the other group. After the plants grow for four weeks, the students count how many flowers each plant has made.
What does this experimental investigation lack?

a control group
an independent variable
a dependent variable
a procedure

TROLL ANSWERS WILL BE REPORTED
Physics
2 answers:
professor190 [17]3 years ago
7 0

sorry if im incorrect. I believe its a dependent variable

pashok25 [27]3 years ago
3 0

Sorry if this isn't correct as it's been quite a while since i've learned this subject but I believe that the answer is dependant variable because the dependant variable would be the number of flowers on the plants and everything else seems to be in check

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A 2.60 kg lion runs at a speed of 5.00 m/s until he sees his prey. The lion then speeds up 8.00 m/s to catch it. How much work d
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Answer: 50.7 J

Explanation:

Given

mass of lion is  m=2.6\ kg

The initial speed of the lion is v_1=5\ m/s

increased speed of lion is v_2=8\ m/s

Initially, its kinetic energy is K_1=\frac{1}{2}mv_1^2

Final kinetic energy k_2=\frac{1}{2}mv_2^2

work did by lion after speed up is k_2-k_1

\Rightarrow W=\dfrac{1}{2}\times 2.6[8^2-5^2]\\\\\Rightarrow W=1.3\times [39]=50.7\ J

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2 years ago
Show all your work clearly on the scratch paper) Two in-phase loudspeakers that emit sound with the same frequency are placed al
Darya [45]

Answer:

Explanation:

The speed of sound in air to be 343 m/s.

Given:

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Since

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λ/2 = (1 x 5)/12

λ = 0.833m

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8 0
3 years ago
What is quantic fisic
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3 0
3 years ago
Light of wavelength 441.1 nm falls on two slits spaced 0.29 mm apart. What is the required distance from the slits to the screen
pshichka [43]

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d = distance between slits = 0.29mm = 2.9×10^-4m

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Hence R = (4×10^-3) ×(2.9×10^-5)/2×441.4×10^-9

R = 1.16 × 10^-7/8.828×10^-7

R = 1.16/8.828

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