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nevsk [136]
3 years ago
11

We are constantly surrounded by many types of energy transfers and transformations, showing that energy in a system is conserved

. Which of these statements are true about how energy is conserved through transfers and transformations? Choose the two that apply. A. Energy is conserved when a lamp is turned on because some of the electrical energy is transferred into thermal energy. B. Energy is conserved when thermal energy is transferred from your body to a coat. C. Energy is conserved when some of the chemical energy from burning a candle is transformed into thermal energy, while the rest of the chemical energy is transformed into light energy. D. Energy is conserved when electrical energy from a hair dryer is transferred into thermal energy and then transformed by conduction.
Physics
1 answer:
MariettaO [177]3 years ago
5 0

Answer:

Energy is conserved when some of the chemical energy from burning a candle is transformed into thermal energy, while the rest of the chemical energy is transformed into light energy.

Energy is conserved when thermal energy is transferred from your body to a coat.

Explanation:

The principle of conservation of energy states that energy can neither be created nor destroyed, but can be transformed from one form to another. This can be regarded as the first law of thermodynamics.

In the answer, we see two major kinds of energy transformation around us. The both cases show the conservation of energy in a system.

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If a battery causes a wire to carry a current of 4 Amps how many coulombs of charge flow past any point in the wire in 3 seconds
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According to above question ~

  • Current (I) = 4 Amperes

  • Time (t) = 3 seconds

  • Charge (q) = ?

Let's find the charge (q) by using formula ~

  • I =  \dfrac{q}{t}

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Two balls are dropped from rest and allowed to fall. If one ball is allowed to fall for 1 s and the other for 3 s compare the di
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The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.

The given parameters;

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  • time of fall of the second ball, t = 3 s

The distance traveled by each ball is calculated using the second equation of motion as shown below.

The distance traveled by the first ball is calculated as follows;

h = u_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 1^2)\\\\h = 4.9 \ m

The distance traveled by the second ball is calculated as follows;

h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 3^2)\\\\h = 44.1\ m

Thus, the second ball traveled a greater distance because it spent more time in motion.

Learn more here:brainly.com/question/5868480

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