The range of horizontal projectile motion is 3737.5 m.
A projectile's horizontal velocity is constant (a never changing value), Gravity causes a downward vertical acceleration with a magnitude of 9.8 m/s/s. A projectile's vertical velocity fluctuates by 9.8 m/s per second, A projectile's vertical motion is unrelated to its horizontal motion. we know that sinθ is maximum at 90°. Therefore horizontal range will maximum at 45°.
To calculate the range of horizontal projectile motion we use;
Δx = vₓ t
where , Δx = Range
vₓ = Velocity
t = Time
Initial horizontal velocity, vₓ = 650 m/s
Time = 5.75 sec
Δx = 650 × 5.75
= 3737.5 m
Therefore, the range of horizontal projectile motion is 3737.5 m.
Learn more about projectile motion here:
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Answer:
The displacement of the car is 10 km at an angle of 36.9 degrees.
Explanation:
(AP) A car travels 8.00 km west from A to B; then the car travels 6.0 km north from B to C. Calculate the total displacement of the car? to. 10 km 36.9 ° b. 10 km 34.8 ° c. 12 km 34.8 ° d. 12 km 34.8 ° e. 12 km 35.9 °
It is given that,
A car travels 8.00 km west from A to B
The car travels 6.0 km north from B to C
We need to find the total displacement of the car. Initially, the car is moving due west and then it moves due north. So, the displacement of the car is given by :
To find angle,
So, the displacement of the car is 10 km at an angle of 36.9 degrees.