1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anna [14]
3 years ago
6

COCl2(g) decomposes according to the equation above. When pure COCl2(g) is injected into a rigid, previously evacuated flask at

690 K, the pressure in the flask is initially 1.0 atm. After the reaction reaches equilibrium at 690 K, the total pressure in the flask is 1.2 atm. What is the value of Kp for the reaction at 690 K?
Chemistry
1 answer:
mestny [16]3 years ago
3 0

<u>Answer:</u> The value of K_p for the reaction at 690 K is 0.05

<u>Explanation:</u>

We are given:

Initial pressure of COCl_2 = 1.0 atm

Total pressure at equilibrium = 1.2 atm

The chemical equation for the decomposition of phosgene follows:

                  COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)

Initial:            1                    -         -

At eqllm:       1-x                 x        x

We are given:

Total pressure at equilibrium = [(1 - x) + x+ x]

So, the equation becomes:

[(1 - x) + x+ x]=1.2\\\\x=0.2atm

The expression for K_p for above equation follows:

K_p=\frac{p_{CO}\times p_{Cl_2}}{p_{COCl_2}}

p_{CO}=0.2atm\\p_{Cl_2}=0.2atm\\p_{COCl_2}=(1-0.2)=0.8atm

Putting values in above equation, we get:

K_p=\frac{0.2\times 0.2}{0.8}\\\\K_p=0.05

Hence, the value of K_p for the reaction at 690 K is 0.05

You might be interested in
When the reaction
yaroslaw [1]
We can express the rate equation in this form:
-r = k A^n B^m

where -r is the rate
k is the rate constant,
A is the concentration of CH3Cl
n is the order with respect to CH3Cl
B is the concentration of H2O
m is the order with respect to H2O

We can solve this by trial and error or by calculus. The first method is easier. The rate constant does not depend on the concentration of the reactant. Assume values of n and m and solve for k in each experiment. The only option that gives really close values of k in each experiment is:
<span>C. CH3Cl: firstorder H2O: second order
</span>
3 0
4 years ago
A student measures the mass of a clean, dry flask and stopper is measured using a laboratory balance. The mass of the empty stop
Jobisdone [24]

Answer:

Volume of flask = 29.134 cm³

Explanation:

Mass of water = mass of filled stoppered flask - mass of empty stoppered flask.

Mass of water = 65.858 - 36.724 = 29.134 g

Density of water = 1 g/cm³

Volume = mass/ density

Volumeof water = 29.134 g/ 1g/cm³ = 29.134cm³

Therefore, volume of flask = 29.134 cm³

7 0
3 years ago
Read 2 more answers
Perform the following
tensa zangetsu [6.8K]
The correct answer is 2.05 !!
7 0
2 years ago
PLEASE ANSWER
vodka [1.7K]

Answer:

  • <u><em>B. Negative association</em></u>

<u><em></em></u>

Explanation:

<em>Negative association</em> is when the independent and dependent variables move in opposite directions: if the dependent variable increases, the independent variable decreases, and if the dependent variable decreases, the independent variable increases.

As you see in the diagram, as you move to the right on the horizontal axis, meaning that the independent variable is increasing, the points lie lower, meaning that the independent variable decreases.

Therefore, if you draw a line of best fit, it will have a negative slope. A negative slope indicates <em>negative association.</em>

The graph certainly shows association as there is a clear trend; else the points would be randomly dispersded.

7 0
3 years ago
A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur
dsp73

Answer:

12.8 g of O_{2} must be withdrawn from tank

Explanation:

Let's assume O_{2} gas inside tank behaves ideally.

According to ideal gas equation- PV=nRT

where P is pressure of O_{2}, V is volume of O_{2}, n is number of moles of O_{2}, R is gas constant and T is temperature in kelvin scale.

We can also write, \frac{V}{RT}=\frac{n}{P}

Here V, T and R are constants.

So, \frac{n}{P} ratio will also be constant before and after removal of O_{2} from tank

Hence, \frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}

Here, \frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm} and P_{after}=17atm

So, n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol

So, moles of O_{2} must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of O_{2} = 32 g/mol

So, mass of O_{2} must be withdrawn = (32\times 0.40)g=12.8g

7 0
3 years ago
Other questions:
  • Which of the following most likely explains why the chemical symbol for calcium is Ca?
    5·1 answer
  • How did Rutherford discredit Thomson's plum pudding model of an atom?
    13·2 answers
  • A gas is contained in a 5.0–liter container at a pressure of 100 kPa. What size container would be required to contain the gas a
    12·2 answers
  • What is an advantage of some sources<br> of renewable energy over<br> nonrenewable energy sources?
    6·1 answer
  • Rank the formation of the solutions A, B, and C from the most exothermic to the most endothermic. Rank the enthalpy of solution
    9·1 answer
  • A solution contains 50g of kcl per 100g of water at 100 degrees Celsius. Is solution saturated, unsaturated or supersaturated
    8·1 answer
  • What happens when a single called organism grows and divides
    15·2 answers
  • Consider the following reaction: Mg(s) + ZnSO4(aq) → MgSO4(aq) + Zn(s) Which of the following statements regarding this reaction
    15·2 answers
  • I NEED HELP ASAP PLZ LOOK AT THE PICTURE CAREFULLY!!!!
    7·1 answer
  • What is the relationship between cubic centimeters and milliliters?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!