Answers:
Hydrogen bond is formed when positive end of one molecule attracted negative end of other molecule. The concept is similar to magnetic attraction where opposite poles attract each other.
Explanation:
While understanding hydrogen bond, two terms are important, one is electronegativity (tendency of atoms to attract electrons towards itself) and other is dipole (separation of positive and negative charge in a molecule). Hydrogen bond is always formed between hydrogen atom and other atoms having electronegativity different than hydrogen.
Differ from Ionic and Covalent Bonds:
Hydrogen bond is weaker than ionic and covalent bond. Ionic and covalent bonds are intramolecular (within the molecule) whereas hydrogen bond is intermolecular (between molecules).
Example:
Formation of hydrogen bonding in water.
Answer:
the energy should be potential
Br
First of all, As is a metalloid, not a nonmetal. Second of all, as the rows get higher on the periodic table, the elements are more reactive. As you move right on the periodic table, the elements become more reactive.
Answer:
Thermal energy consists of the total internal kinetic energy of an object due to the random motion of its atoms and molecules. It is related to heat and temperature.
Explanation:
Answer:
The correct answer is option D.
Explanation:
The chemical equation for the conversion follows:

The expression for
of above equation is:
![K_{eq}=\frac{\text{[fructose 6-phosphate]}}{\text{[glucose 6-phosphate]}}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5Ctext%7B%5Bfructose%206-phosphate%5D%7D%7D%7B%5Ctext%7B%5Bglucose%206-phosphate%5D%7D%7D)

where,
= standard Gibbs free energy = 1.72 kJ/mol = 1720 J/mol (Conversion factor: 1kJ = 1000J)
R = Gas constant =
(given)
T = temperature =298K
Putting values in above equation, we get:
![1720 J/mol=-(8.315J/Kmol)\times 298K\times \ln (\frac{\text{[fructose 6-phosphate]}}{\text{[glucose 6-phosphate]}})](https://tex.z-dn.net/?f=1720%20J%2Fmol%3D-%288.315J%2FKmol%29%5Ctimes%20298K%5Ctimes%20%5Cln%20%28%5Cfrac%7B%5Ctext%7B%5Bfructose%206-phosphate%5D%7D%7D%7B%5Ctext%7B%5Bglucose%206-phosphate%5D%7D%7D%29)
![\frac{\text{[fructose 6-phosphate]}}{\text{[glucose 6-phosphate]}}=0.499\approx = 0.5=\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B%5Bfructose%206-phosphate%5D%7D%7D%7B%5Ctext%7B%5Bglucose%206-phosphate%5D%7D%7D%3D0.499%5Capprox%20%3D%200.5%3D%5Cfrac%7B1%7D%7B2%7D)
![\frac{\text{[fructose 6-phosphate]}}{\text{[glucose 6-phosphate]}}=\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B%5Bfructose%206-phosphate%5D%7D%7D%7B%5Ctext%7B%5Bglucose%206-phosphate%5D%7D%7D%3D%5Cfrac%7B1%7D%7B2%7D)
The ratio of glucose 6-phosphate to fructose 6-phosphate at equilibrium :
![\frac{\text{[glucose 6-phosphate]}}{\text{[fructose 6-phosphate]}}=\frac{2}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B%5Bglucose%206-phosphate%5D%7D%7D%7B%5Ctext%7B%5Bfructose%206-phosphate%5D%7D%7D%3D%5Cfrac%7B2%7D%7B1%7D)