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myrzilka [38]
4 years ago
11

Two similar polygons are shown below:

Mathematics
2 answers:
Mice21 [21]4 years ago
6 0
The correct answer would be a dialation of 1 over 3 as P'Q'R'S' is smaller than PQRS and its a third of its size.
Kobotan [32]4 years ago
3 0

Answer:  The correct set of transformations is (B) A dilation factor of 1 over 3.

Step-by-step explanation:  We are given to similar polygons PQRS and P'Q'R'S'.

We are to select the correct set of transformations that was performed on the polygon PQRS to form P'Q'R'S'.

Since the two polygons PQRS and P'Q'R'S' are similar, so there will be a dilation with a dilation (scale) factor.

We need to find the dilation factor of the dilation.

In P'Q'R'S', the length of a side is given by

P'Q' = 2 units,

and the length of the corresponding side in PQRS is given by

PQ = 2 units.

Therefore, the dilation factor of dilation is

D=\dfrac{\textup{length of a side of }P'Q'R'S'}{\textup{length of the corresponding side in }PQRS}\\\\\\\Rightarrow S=\dfrac{P'Q'}{PQ}=\dfrac{2}{6}=\dfrac{1}{3}.

Thus, there will be a dilation with a dilation factor of \dfrac{1}{3}.

Option (B) is correct.

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3. Solve for x. Round to the nearest tenth.<br> 14<br> х<br> 49°
Elis [28]
So for this triangle you are going to use Cos, which is adjacent/hypotenuse.
In this case x is your hypotenuse.

So your equation is going to be Cos(49)= 14/x.
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4 0
3 years ago
Heyy besties can ya'll please help me with 1 to 4 im really left behind
hram777 [196]

Answer:

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2nd one: 260

3rd one: 210

4th one: 72

Step-by-step explanation:

here are the actual answers since the other person who "answered" is clearly just hungry for points

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A 7th grade math class is having a year end party. So far, 16 students have paid a total of $132.
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Answer:

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