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Mashutka [201]
3 years ago
5

3

Chemistry
1 answer:
Zina [86]3 years ago
5 0

Answer:

Explanation:

n CaCO3 = mass / m.wt

             = 500  /( 40 + 12 + 16x 3)

           =   5 mole

n CaO = 5 moles  ( from the balanced equation we have 1:1 moles )

mass of CaO = nCaO X m.wt

                       5 x(  40 +16 )

                 =   280 grams

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Jack has a rock. The rock has a mass of 14 g and a volume of 2 cm3. What is the density of the rock? * 0 7 ml O 28 g/cm3 07 g/cm
jeyben [28]

Answer:

The answer is

<h2>7.0 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass of rock = 14 g

volume = 2 cm³

The density of the rock is

density  = \frac{14}{2}  \\

We have the final answer as

<h3>7.0 g/cm³</h3>

Hope this helps you

3 0
4 years ago
The Ka of hydrazoic acid (HN3) is 1.9 × 10-5 at 25.0 °C. What is the pH of a 0.40 M aqueous solution of HN3?
siniylev [52]

Answer:

The pH of the solution is 2.56.

Explanation:

Given :

Concentration (c) = 0.40 M

Acid dissociation constant = K_a=1.9\times 10^{-5}

The equilibrium reaction for dissociation of HN_3 (weak acid) is,

                           HN_3+H_2O\rightleftharpoons N_3^{-}+H_3O^+

initially conc.         c                       0         0

At eqm.              c(1-\alpha)                c\alpha        c\alpha

Dissociation constant is given as:

K_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}

1.9\times 10^{-5}=\frac{(0.40\alpha)(0.40\alpha)}{0.40(1-\alpha)}

By solving the terms, we get value of (\alpha)}

\alpha=0.00686832

No we have to calculate the concentration of hydronium ion or hydrogen ion.

[H^+]=c\alpha=0.4\times 0.00686832=0.002747 M

Now we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.002747)

pH=2.56

Therefore, the pH of the solution is, 2.56.

8 0
4 years ago
The element silver (Ag) has two naturally occurring isotopes: 109Ag and 107Ag with a mass of 106.905 amu. Silver consists of 51.
algol [13]

Answer:

108.76 amu is the mass of 109Ag

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, 109Ag:

% = 51.82 %

Mass = x amu

For second isotope, 107Ag:

% = 100  - x   = 100 - 51.82 % = 48.18 %

Mass = 106.905 amu

Given, Average Mass = 107.868 amu

Thus,  

107.868=\frac{51.82}{100}\times {x}+\frac{48.18}{100}\times {106.905}

Solving for x, we get that:

x = 108.76 amu

<u>108.76 amu is the mass of 109Ag</u>

6 0
3 years ago
How many moles are in 9.8 grams of calcium?
Alexxx [7]
The answer is 0.24 moles.
8 0
3 years ago
The part of an atom where nearly whole mass is<br> concentrated is called
qwelly [4]

Answer:

.....is called nucleus which have a positive charge the positive charge in the nucleus is balanced by the negative electrons making an atom neutral

3 0
3 years ago
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