A option will be the answer.
Answer:
(b) 2.40 x
kg/s
Explanation:
Given that: Total mass of the rocket = 3.003 x
kg
acceleration of the rocket = 36.0 m![s^{-2}](https://tex.z-dn.net/?f=s%5E%7B-2%7D)
speed of the exhausted gases = 4.503 x
m/s
Rate at which rocket was initially burning fuel = ![\frac{mass}{time}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Btime%7D)
But,
time = ![\frac{velocity}{acceleration}](https://tex.z-dn.net/?f=%5Cfrac%7Bvelocity%7D%7Bacceleration%7D)
= ![\frac{4.503*10^{3} }{36.0}](https://tex.z-dn.net/?f=%5Cfrac%7B4.503%2A10%5E%7B3%7D%20%7D%7B36.0%7D)
= 125.0833 s
So that;
Rate at which rocket was initially burning fuel = ![\frac{3.003*10^{5} }{125.0833}](https://tex.z-dn.net/?f=%5Cfrac%7B3.003%2A10%5E%7B5%7D%20%7D%7B125.0833%7D)
= 2400.8001
= 2.40 x
kg/s
Therefore, the initial rate at which the rocket burn fuel is 2.40 x
kg/s.
Answer:
here is what i found i hope it helps answer your question ❤ have a good rest of your day <em>-ANGIEEE</em>
Explanation:
Answer:
The angle between the diagonal and edge = 55 degrees
Explanation:
We will find it by finding the angle between two vectors (a and b)
We will assume it to be a unit cube
Vector a = (1,1,1) (defines the diagonal vector)
Vector b = (1,0,0) (defines the edge vector)
cos (theta) = (a.b)/(|a|*|b|)
![cos (theta) = 1 / (\sqrt{3} * \sqrt{1} )](https://tex.z-dn.net/?f=cos%20%28theta%29%20%3D%201%20%2F%20%28%5Csqrt%7B3%7D%20%2A%20%5Csqrt%7B1%7D%20%20%29)
theta = 54.74 degrees
theta = 55 degrees (Rounded to the nearest degree)