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Keith_Richards [23]
3 years ago
7

Jak můžeme videt ze se meni cas

Physics
1 answer:
juin [17]3 years ago
3 0

Answer:

a jak to chces vidieť nápis podrobnejsie

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Since the pumpkin is dropped, that means it is in freefall and is accelerating at the acceleration due to gravity. The acceleration due to gravity is 9.81m/s down.
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The electromagnetic waves that have the lowest frequency is called
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Radar waves are the waves with the lowest energy.
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A particular cylindrical bucket has a height of 36.0 cm, and the radius of its circular cross-section is 15 cm. The bucket is em
Sergeeva-Olga [200]

Answer:

a. 0.000002 m

b. 0.00000182 m

Explanation:

36 cm = 0.36 m

15 cm = 0.15 m

a) We can start by calculating the air-water pressure of the bucket submerged 20m below the water surface:

P = \ro g h = 1000 * 10 * 20 = 200000 Pa

Suppose air is ideal gas, then if the temperature stays the same, the product of its pressure and volume stays the same

P_1V_1 = P_2V_2

Where P1 = 1.105 Pa is the atmospheric pressure, V_1 is the air volume in the bucket on the suface:

V_1 = Ah

As the pressure increases, the air inside the bucket shrinks. But the crossection area stays constant, so only h, the height of air, decreases:

P_1Ah_1 = P_2Ah_2

h_2 = h_1\frac{P_1}{P_2} = 0.36\frac{1.105}{200000} = 0.000002 m

b) If the temperatures changes, we can still reuse the ideal gas equation above:

\frac{P_1Ah_1}{T_1} = \frac{P_2Ah_2}{T_2}

h_2 = h_1\frac{P_1T_2}{P_2T_1} = 0.36\frac{1.105 * 275}{200000*300} =0.00000182 m

3 0
4 years ago
Two streams merge to form a river. One stream has a width of 8.9 m, depth of 3.8 m, and current speed of 2.3 m/s. The other stre
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<h2>Depth of river is 4.48 m</h2>

Explanation:

Discharge = Area x Velocity

Discharge of river = Discharge of stream 1 + Discharge of stream 2

A_rv_r=A_1v_1+A_2v_2

Area of stream 1 = w₁ x d₁ = 8.9 x 3.8 = 33.82 m²

Area of stream 2 = w₂ x d₂ = 6.5 x 3.9 = 25.35 m²

Velocity of stream 1 = 2.3 m/s

Velocity of stream 2 = 2.6 m/s

Velocity of river = 3 m/s

\texttt{Area of river = }w_r\times d_r=10.7\times d_r

Substituting

             A_rv_r=A_1v_1+A_2v_2\\\\10.7\times d_r\times 3=33.82\times 2.3+25.35\times 2.6\\\\d_r=4.48m

Depth of river = 4.48 m

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3 years ago
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